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zloy xaker [14]
3 years ago
14

Col

Mathematics
1 answer:
ch4aika [34]3 years ago
5 0

Answer:

40%

Step-by-step explanation:

i just looked at it

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23,000,022 = 1<br> use the operation symbole
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291-2999=10376 square feet
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2 years ago
traingle ABC has been dilated aboit point A by a scale factor of 1/3. What are the lengths, in units, of the three sides of tria
solniwko [45]

Answer:

You need to show the graph so i can see numbers, you cant dilate the traingle without knowing where it is on the graph.

Step-by-step explanation:

4 0
3 years ago
When a decimal is written in word form, what indicates whether the number can be written as a mixed number or as a fraction less
vekshin1

9514 1404 393

Answer:

  "and"

Step-by-step explanation:

Properly written, the word "and" separates the integer portion from the fractional portion of the number. If there is no "and", then there is no integer portion, so the number is a fraction less than 1.

<u>Examples</u>:

one <em>and</em> three tenths = 1 3/10

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8 0
2 years ago
Help with 6 a and b please
34kurt

Answer:

a) y=\frac{50}{x}

b) y=25 when x=2

Step-by-step explanation:

y=\frac{k}{x} since y varies inversely with x.

We need to find the constant, k.

Let's use a point (x,y) on the curve.

We are given an (x,y)=(5,10):

10=\frac{k}{5}

Multiply both sides by 5:

10(5)=k

50=k.

So the equation is:

y=\frac{50}{x}

What is y when x=2?

y=\frac{50}{2}

y=25

8 0
3 years ago
For the matrices below. Find all (real) eigenvalues. <br><br> A= [7 9]<br> [0 9]
Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]

Using formula:

|A-\lambda \cdot I|= 0\\\\

\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\

\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\

8 0
3 years ago
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