"assume that josh throws the discus 36 times. let y denote the sum of the lengths of the 36 throws.

1 answer:

6 0

<span>Assuming that Josh throws the discus 36 times, the expected value of y will be the length each discus reaches for each throw all added together. Specifically, it will be discus throw one, plus discus throw two -- all the way to discus throw thirty-six. Adding all of those throws together will provide the expected value of Y.</span>

You might be interested in

P(A)=0.36P(B)=0.37P(AandB)=

Simora [160]

Answer:

For the following event probabilities: P(A)=0.36, P(B)=0.37, P(C)=0.27, P(D|A)=0.069, P(D|B)=0.090, P(D|C)=0.076, calculate P(C|D).

Step-by-step explanation:

7 0

2 years ago

Solve 2x^2 +16x+50=0

musickatia [10]

$2x^2 +16x+50=0\ \ \ \ \ |:2\\\\x^2+8x+25=0\\\\x^2+2\cdot x\cdot4+25=0\ \ \ \ |+4^2\\\\\underbrace{x^2+2\cdot x\cdot4+4^2}_{(a+b)^2=a^2+2ab+b^2}+25=4^2\ \ \ \ \ |-25\\\\(x+4)^2=16-25\\\\(x+4)^2=-9 < 0-NO\ REAL\ SOLUTION$

$COMPLEX\ SOLUTIONS\\\\(x+4)^2=-9\to x+4=\pm\sqrt{-9}\\\\x+4=-3i\ \vee\ x+4=3i\ \ \ \ |-4\\\\x=-4-3i\ \vee\ x=-4+3i$

5 0

2 years ago

Drag expressions into order to show a way to find 3 × 56.

lina2011 [118]

As we could "drag" these together, we could then do it the easy way.

56
+56
+56
-------
168
------------------------

Or we could also do the following:

56 $*$ 3:

6 $*$ 3= 18.

Carry the one.

5 $*$ 3 = 15+1 (which was carried). = 16

(16+8) = 168

7 0

3 years ago

Read 2 more answers

What is the measure of the major arc?

ehidna [41]

Answer:

C. 225°.

Step-by-step explanation:

1) according to the condition minor arc is 135°;

2) the measure of the major arc can be calculated as

360°-135°=225°.

5 0