Hey There !:
Molar mass of H₂O = 18.01 g/mol
Therefore:
1 mol H₂O ----------------- 18.01 g/mol
9.00 moles ---------------- ( mass of H₂O )
mass of H₂O = 9.00 x 18.01 / 1
mass of H₂O = 162.09 / 1
mass of H₂O = 162.09 grams
I hope that it helps !
Answer:
Total concentration of ions present in the final solution is 0.0726 M.
Explanation:
Mass of silver nitrate = 54.0 g
Moles of silver nitrate =
Volume of the solution made = V = 350.0 mL = 0.350 L
After dilution of 10.00 mL 0.9227 M solution.
Concentration of silver nitrate after dilution = 0.0363 M
Total concentration of ions present in the final solution:
Answer:
153.6771 amu
Explanation:
From the question given above, the following data were:
Isotope A:
Mass of A = 114.3789 amu
Abundance (A%) = 64.23%
Isotope B:
Mass of B =.?
Abundance (B%) = 100 – A%
Abundance (B%) = 100 – 64.23
Abundance (B%) = 35.77%
average atomic mass of Element Y = 128.4359 amu
The mass of the 2nd isotope (i.e isotope B) can be obtained as follow:
Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
128.4359 = [(114.3789 × 64.23)/100] + [(Mass of B × 35.77) /100]
128.4359 = 73.4656 + (Mass of B × 0.3577)
Collect like terms
128.4359 – 73.4656 = Mass of B × 0.3577
54.9703 = Mass of B × 0.3577
Divide both side by 0.3577
Mass of B = 54.9703 / 0.3577
Mass of B = 153.6771 amu
Therefore, the mass of the 2nd isotope is 153.6771 amu
The answer would be letter b