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timurjin [86]
3 years ago
13

When the temperature in a room increases from 25c to 33c what changes from a solid to a liquid

Chemistry
2 answers:
Contact [7]3 years ago
8 0
58 would be your answer
Anastasy [175]3 years ago
3 0

Answer:

Gallium

Explanation:

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Two skydivers jump out of a plane. As the skydivers are in free fall, the potential energy they possessed at the airplane door I
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That is true, the potential energy they possessed at the airplane door would be converted to kinetic energy. And if they driver is high up, he has further to fall. As the skydivers jump, the energy would be converted to kinetic energy.
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Automobile catalytic converters use a platinum catalyst to reduce air pollution by changing emissions such as carbon monoxide, C
julia-pushkina [17]

Answer: 448 g of O_2 will be required to completely react with 784g moles of CO(g) during this reaction.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} CO=\frac{784g}{28g/mol}=28moles

The balanced chemical equation is:

2CO(g)+O_2(g)\rightarrow 2CO_2(g)  

According to stoichiometry :

2 moles of CO require  = 1 mole of O_2

Thus 28 moles of CO will require=\frac{1}{2}\times 28=14moles  of O_2

Mass of O_2=moles\times {\text {Molar mass}}=14moles\times 32g/mol=448g

Thus 448g of O_2 will be required to completely react with 784g moles of CO(g) during this reaction.

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3 years ago
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An aqueous solution of glycerol, c3h8o3, is 48.0% glycerol by mass and has a density of 1.120 g ml-1. calculate the molality of
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Answer is: <span>the molality of the glycerol solution is 10.03 m.
V(solution) = 100 mL.
m</span>(solution) = V(solution) · d(solution).
m(solution) = 100 mL ·1.120 g/mL.
m(solution) = 112 g.
m(glycerol) = ω(glycerol) · m(solution).
m(glycerol) = 0.48 · 112 g.
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m(water) = 58.24 g ÷ 1000 g/kg = 0.05824 kg.
n(C₃H₈O₃) = m(C₃H₈O₃) ÷ M(C₃H₈O₃).
n(C₃H₈O₃) = 53.76 g ÷ 92 g/mol.
n(C₃H₈O₃) = 0.584 mol.
b(C₃H₈O₃) = n(C₃H₈O₃) ÷ m(H₂O).
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HCl + Ca(OH)2 = CaCl2 + H2O - Chemical Equation Balancer.

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