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3 years ago

PLEASE HELP WILL MARK BRAINLIEST!

2 answers:

8 0

A substance is essentially a species of matter having a definite chemical composition . A number of substances can combine to form a mixture. Pure substances are composed of a single element or compounds. Combinations of different substances are called mixtures. Homogeneous mixtures are mixtures of two or more compounds (or elements) that are not visually distinguishable from each other.

In the classical physics observed in everyday life, matter is any substance that has mass and takes up space by having volume. This includes atoms and anything made up of these, but not other energy phenomena or waves such as light or sound. More generally, however, in (modern) physics, matter is not a fundamental concept because a universal definition of it is elusive; for example, the elementary constituents of atoms may be point particles, each having no volume individually.

garik1379 [7]3 years ago

5 0

Answer:

Pure substances are further broken down into elements and compounds. Mixtures are physically combined structures that can be separated into their original components. ... A heterogeneous mixture is a mixture of two or more chemical substances where the various components can be visually distinguished.

Explanation:

hopes this helps. :)

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3 years ago

Standard reduction half-cell potentials at 25∘c half-reaction e∘ (v) half-reaction e∘ (v) au3 (aq) 3e−→au(s) 1.50 fe2 (aq) 2e−→f

Zanzabum

K = 5.0 × 10^25

<h2>Part (a). Calculate E° for the reaction </h2>

Step 1. Write the equations for the two half-reactions

2H^(+)(aq) + 2e^(-) → H2(g); _0.00 V

Zn^(2+)(aq) + 2e^(-) → Zn(s); -0.76 V

Step 2. Identify the cathode and the anode

The half-cell with the more negative E° (Zn) is the anode.

Step 3. Calculate E°

Zn(s) → Zn^(2+)(aq) + 2e^(-); _________+0.76 V

2H^(+)(aq) + 2e^(-) → H2(g); __________0.00 V

Zn(s) + 2H^(+)(aq) → Zn^(2+)(aq) + H2(g); +0.76 V

E° = +0.76 V

<h2>Part (b). Calculate K for the reaction </h2>

The relation between E° and K is

E° = (RT)/(nF)lnK

where

R = the universal gas constant: 8.314 J·K^(-1)mol^(-1)

T = the Kelvin temperature

n = the moles of electrons transferred

F = the Faraday constant: 96 485 J·V^(-1)mol^(-1)

Then

0.76 V = [8.314 J·K^(-1)mol^(-1) × 298.15 K]/[2 × 96 485 J·V^(-1)mol^(-1)]lnK

0.76 = 0.012 85 lnK

lnK = 0.76/0.012 85 = 59.16

K =e^59.16 = 5.0 × 10^25

4 0

3 years ago

Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pr

Delvig [45]

<h2>Hello!</h2>

The answer is: Charle's Law.

The law that states that the volume and absolute temperature of a fixed quantity of gas (ideal gas) are proportional under constant pressure is the Charle's Law, also known as the law of volumes.

The law describes how a gas kept under constant pressure tends to expand when the temperature increases and it's described by the following equation:

$\frac{V}{T}=k$