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3 years ago

5

Given the incomplete equation representing a reaction:

2 answers:

dmitriy555 [2]3 years ago

4 0

(bla bla bla because answer must be between 20 and 5000 characters long of )
it will be OH- (aq)

sergey [27]3 years ago

3 0

Answer : The formula of the missing product is, $OH^_$

Explanation :

The given incomplete equation representing a reaction,

$2Na(s)+2H_2O(l)\rightarrow 2Na^+(aq)+2__(aq)+H_2(g)$

When the sodium metal react with the water then it gives a colorless solution of sodium hydroxide and hydrogen gas. In the solution, sodium hydroxide is present in the form of ions i.e, $Na^+$ and $OH^-$ ions.

The balanced chemical reaction will be,

$2Na(s)+2H_2O(l)\rightarrow 2Na^+(aq)+2OH^-(aq)+H_2(g)$

Therefore, the formula of the missing product is, $OH^_$

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Licemer1 [7]

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Sphinxa [80]

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3 years ago

Read 2 more answers

A 0.200 M solution of a weak acid, HA, is 9.4% ionized. Using this information, calculate Ka for HA.

slavikrds [6]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

Initial concentration of weak acid HA = 0.200 M

and dissociation constant ( ${ \alpha}$ ) is :

$\qquad \sf \dashrightarrow \: \alpha = \frac{dissociation \: \: percentage}{100}$

$\qquad \sf \dashrightarrow \: \alpha = \frac{9.4}{100} = 0.094$

Now, at initial stage :

$\textsf{ Conc of HA = 0.200 M}$

$\textsf{Conc of H+ = 0 M}$

$\textsf{Conc of A - = 0 M}$

At equilibrium :

$\textsf{Conc of HA = 0.200 - 0.094(0.200) = 0.200(1 - 0.094) = 0.200(0.906) = 0.1812 M}$

$\textsf{Conc of H+ = 0.094(0.200) = 0.0188 M}$

$\textsf{Conc of A - = 0.094(0.200) = 0.0188 M}$

Now, we know :

$\qquad \sf \dashrightarrow \: { K_a = \dfrac{[H+] [A-]}{[HA]}}$

( big brackets represents concentration )

$\qquad \sf \dashrightarrow \: { K_a = \dfrac{0.0188×0.0188}{0.1812}}$

$\qquad \sf \dashrightarrow \: { K_a = \dfrac{0.00035344}{0.1812}}$

$\qquad \sf \dashrightarrow \: { K_a \approx 0.00195 }$

$\qquad \sf \dashrightarrow \: {K_a \approx 1.9 × {10}^{-3} }$

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2 years ago

What is the uncertainty of a 10ml pipet?

EleoNora [17]

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3 years ago