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disa [49]
4 years ago
11

Write an equation that passes through the points (4,-1) and (2,- 2).

Mathematics
1 answer:
jenyasd209 [6]4 years ago
6 0
y=  1/2(x)-3
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What is the solution to the inequality 14y−14≥14?
makkiz [27]
14y > 0 is the answer
6 0
3 years ago
Read 2 more answers
Please help me with this
polet [3.4K]
1 , 5
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15

i think this is right
5 0
3 years ago
−20 ≤ 59(F−32) ≤ −15
lubasha [3.4K]
We take the value of F in the inequality by taking the inequalities in group. Let the first group be:

(1)    -20 ≤ 59(F - 32)

Then, the second group would be,
(2)     59(F - 32) ≤ - 15

Calculating for the values of F,

(1)     -20 ≤ 59F - 1888
          1888 - 20 ≤ 59F
              1868 ≤ 59F
                 F ≥ 31.66

(2)     (59)(F - 32) ≤ - 15
             59F - 1888 ≤ -15
             59F ≤ 1873
                F ≤ 31.75

The values of F are therefore,
               31.66 ≤ F ≤ 31.75

7 0
3 years ago
A person gets on a Ferris wheel at the starting point. The starting point is 15 feet off the ground. The Ferris wheel has a radi
lisov135 [29]
<h2>Answer:</h2>

\boxed{\frac{25}{2}(\sqrt{6}+\sqrt{2})+65}

<h2>Explanation:</h2>

<em>The height of the rider from the ground after the Ferris wheel</em> equals <em>the starting point is 15 feet off the ground </em><em>plus </em><em>the radius of the Ferris wheel </em><em>plus </em><em>the opposite side of the triangle ΔABC </em>(See figure below).<em> </em>Hence our goal is to find this side. We have the angle 11\pi /2=165^{\circ}, therefore the angle ∠BAC = 165° - 90° = 75°. So this side can be found using trigonometry:

\overline{BC}=\overline{AB}sin(75^{\circ})=50sin(75^{\circ})=\frac{25}{2}(\sqrt{6}+\sqrt{2})

Finally, the height is:

H=\frac{25}{2}(\sqrt{6}+\sqrt{2})+15+50 \\ \\ \boxed{H=\frac{25}{2}(\sqrt{6}+\sqrt{2})+65}

6 0
3 years ago
Help please!!!!!!!!!!
scZoUnD [109]

Answer:

f ( x ) = x² - 1

Step-by-step explanation:

hope this will help

7 0
3 years ago
Read 2 more answers
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