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makvit [3.9K]
3 years ago
15

Todd is 30 years old. If his target heart rate during aerobic activity is 60-90 % of his maximum heart rate, how fast should his

heart beat during exercise (in beats/min)?
Mathematics
1 answer:
sergeinik [125]3 years ago
6 0

Answer:

Step-by-step explanation:

It is given that Todd is 30 year old and he perform aerobic activity that may increase his heart beat.

maximum heart beat can be calculated by subtracting the age from 220

For 30 year old male Maximum heart beat

=220-30=190

And during exercise his heart beat increases to  60-90 % of maximum value

60 % of 190=114 beats/min

90 % of 190=171 beats/min

So Heart beat can goes up to 114 - 171 beats/min

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attashe74 [19]

3(9z+4) > 35z - 4

27z + 12 > 35z - 4

12 + 4 > 35z - 27z

16 > 8z

\frac{16}{8}  > z

2 > z

4 0
2 years ago
For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

  • Divide row 1 by 2 \left(R_1=\frac{R_1}{2}\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

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  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

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\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

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Answer:

false

Step-by-step explanation:

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