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BabaBlast [244]
3 years ago
14

How would you solve this: x^2-9x+18

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
7 0
Hope this helps you!!!

gulaghasi [49]3 years ago
7 0

Hello!

To factor this, we will want to find the GCF of all of these numbers. It cannot involve x, as 18 is a constant.

x·x-9x+18

As you can see, there is no common factor, so we cannot multiply a parentheses by one number. What we can do, though, is multiply two parentheses. We can use the FOIL method, which means that to unfactor two parentheses, you multiply the first numbers, outside, inside, and last. Let's try doing so.

(a,b)(y,z)

First of all, a multiplied by x will probably have to equal x², as it appears first. This means a and x are x.

(x,b)(x,z)

As you can see, the outside and inside are both going to have an x in them. This means that we will want some numbers that will add to make -9, and will multiply to make 18. If you think about it, -3 and -6 would work.

-3+-6=-9

-3(-6)=18

Therefore, our factored answer is below.

(x-3)(x-6)

I hope this helps!


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Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1
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<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t   (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ \frac{dx}{dt} = -\sin t

  \frac{dy}{dt} = 2 \cos t

  \frac{dz}{dt} = \sin t-2cos t

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}

=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)

Now evaluating the integral using calculator,

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t) = 13.5191




8 0
3 years ago
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