Question

Y=-8(x+3)(x-2) in standard form

Answer 1

Answer:

$\large\boxed{y=-8x^2-8x+48}$

Step-by-step explanation:

The standard form of an equation of a parabola:

$y=ax^2+bx+c$

We have

$y=-8(x+3)(x-2)$         use distributive property: a(b + c) = ab + ac

$y=\bigg((-8)(x)+(-8)(3)\bigg)(x-2)$

$y=(-8x-24)(x-2)$        use FOIL: (a + b)(c + d) = ac+ ad + bc + bd

$y=(-8x)(x)+(-8x)(-2)+(-24)(x)+(-24)(-2)$

$y=-8x^2+16x-24x+48$        combine like terms

$y=-8x^2+(16x-24x)+48\\\\y=-8x^2-8x+48$