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Murljashka [212]
3 years ago
12

Which is the least common denominator of 5/6 3/8

Mathematics
1 answer:
Tems11 [23]3 years ago
4 0

To find the least common denominator, or lcd, you have to find the least common multiple, or lcm. To do that you find the multiples of each number until they equal each other. I set up a chart like this,

6 -

8 -

and then I start listing multiples so,

6 - 6, 12, 18, 24,

8 - 8, 16, 24,

I stop after I find a number they are both equal to. So to get to that number I would multiply 8 by 3, and 6 by 4. This gives me 24 as the lcd. If you need the lcd to add the fractions together, then whatever you did to the bottom do to the top. So 5/6 would become 20/24 and 3/8 would become 9/24.


Answer: 24

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You could make this really simple by dividing 300 by 4 to see how much 1/4 of that is and then subtracting 1/4 from 300 to see how much dashawn's water bottle holds.

300/4 =75 so 1/4 is equal to 75 mL

300-75=225mL

Dashawn's water bottle holds 225mL
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A media company wants to track the results of his new marketing plan so the video production manager recorded the number of use
konstantin123 [22]

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f(x)=5120(5)^{x}

Step-by-step explanation:

From the image, f(x) and x are rlated by

f(x)=a( {b})^{x}

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\frac{8000}{6400}= 5

\frac{10000}{8000} = 5

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so we can say the common ratio, b=5

we put in any value of f(x) and the corresponding value for x to find a value

Let put x=0 and f(x)=5120

This implies that

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Hence a=5120

Thus the equation which model the relationship between the weeks and the viewers is

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2 years ago
Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ab
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Answer:

test statistic is ≈ -0.36

p-value is  ≈ 0.64

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

Step-by-step explanation:

a hypothesis test where H_0: mu = 235 and H_1:mu > 235

test statistic can be calculated as follows:

z=\frac{X-M}{\frac{s}{\sqrt{N} } } where

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  • M is the average expected distance that the average golfer can hit the ball under null hypothesis. (235 yards)
  • s is the standard deviation (46.6 yards)
  • N is the sample size (192)

Then test statistic is z=\frac{233.8-235}{\frac{46.6}{\sqrt{192} } } =-0.3568

p-value is  0.64 >0.05

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

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