Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
A radius is a straight line from the centre to the edge of a circle. i’m not sure about any examples sorry :/
Answer:
His rate in chapters per hour is 8 chapters per hour
Step-by-step explanation:
If you divide 56 by 7 you get 8 also if you want to check to be sure you can just multiply 8 and 7 or 7 and 8
Answer: y = -4x
Step-by-step explanation: You would use the formula y = mx + b to solve your problem. When you plug the numbers in, you get y = -4x. There would be no "+ b" because in this case, the y-intercept (b) is equal to zero. Therefore, you would not need to write "y = -4x + 0" because that would not be the equation in its simplest form.
Answer:
We also drew a graph with 2 examples.
Step-by-step explanation:
If we have the line segment CD, we can divide it by 4: 1 as follows:
If point C has the coordinates (x1, z1) and point D has the coordinates (x2, z2), we calculate coordinate the points Y as follows:
y1 = (x2-x1) · 4/5
y2 = (z2-z1) · 4/5
In this way we have obtained the point Y with the coordinates (y1, y2), and the point Y divides the line segment CD by 4:1.
We also drew a graph with 2 examples.
