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2 years ago

14

Chase is making a cake for his daughter's birthday. The normal recipe calls for 8 ounces of butter and 16 ounces of sugar. Chase

then decides to make a slightly smaller cake and only use 6 ounces of butter. How many ounces of sugar will he need in his smaller cake?

1 answer:

kotykmax [81]2 years ago

7 0

Answer:

A lot

Step-by-step explanation:

Why am I baking cakes. I SUCK.

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What substitution should be used to rewrite 4x^4-21x^2+20 =0 as a quadratic equation

marysya [2.9K]

I would substitute y = x^2

4y^2 -21y+20=0

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3 years ago

If an experimenter sets equal to .01, then she is defining a "statistically rare" event as an event occurring more than one time

Fynjy0 [20]

Answer:

The correct answer is an event occurring one or fewer times in 100 times if the null hypothesis is true.

Step-by-step explanation:

For a statistically rare event, its probability is relatively small and the event is very unlikely to occur. Therefore, if an experimental sets equal to 0.01 which is statistically rare, then we can interpret this mathematically as:

p(event) = 0.01 = 1/100

where p(event) is the probability of the event.

In addition, statistically, null hypothesis signifies no major difference between the specified parameters, and any obvious difference that might occur as a result of experimental error. Thus, it can be concluded that the event is occurring one or fewer times in 100 times if the null hypothesis is true.

3 0

3 years ago

Where is the constant on here?<br><br> 12+ x - 3.7 - 8y + 1/3

SCORPION-xisa [38]

12-3.7+(1/3)=constant
259/30=constant

6 0

3 years ago

Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the

zlopas [31]

Answer:

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

$\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}$

$\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}$

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

3 0

3 years ago

A circle has an area of 2511 square centimeters. What is the length of its<br> radius?

romanna [79]

Answer:

r=28.27 cm aprox

Step-by-step explanation:

Well you know that the area of a circle is A= $\pi$ $r^{2}$ so

2511= $\pi$ $r^{2}$ so

$r^{2}$ =2511/ $\pi$

r=28.27 cm aprox

8 0

3 years ago

Read 2 more answers