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DENIUS [597]
3 years ago
10

Find the equation of the line.

Mathematics
1 answer:
Grace [21]3 years ago
7 0

Answer:

m:-\frac{1}{3}

Step-by-step explanation:

Pick two points (0,5) and (3,4)

use the formula to find slope: \frac{y2-y1}{x2-x1}

Insert values: \frac{4-5}{3-0}

m:-\frac{1}{3}

:-)

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Approximately 32,300 citizens of a country died in automobile accidents in 2015, express this toll in deaths
eimsori [14]

Roughly 88-89 citizens died in automobile accidents per day.

32,300 is the number of people in one year, so in order to find the daily count we need to divide that number by the number of days in a year, 365.

32,300 ÷ 35 ≈ 88.5

This means that roughly 88-89 citizens died in automobile accidents per day.

7 0
3 years ago
Factor completely 4x4 − 24x3 + 36x2.
ehidna [41]
Factor out 4x² from everybody
4x²(x²-6x+9)
factor inner
what 2 numbers multipliy to gete 9 and add to get -6
-3 and -3
4x²(x-3)(x-3)
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4x²(x-3)²


first option
3 0
3 years ago
Read 2 more answers
What is 1/3 of 6/7. please help very important
SashulF [63]
2 over 7.that is a possible answer.its right
8 0
3 years ago
Help pls I'll give 25 points
RideAnS [48]

Answer:

\text{C. }60

Step-by-step explanation:

<u>Question from image</u>:

"The digits 1, 2, 3, 4, and 5 can be formed to arrange 120 different numbers. How many of these numbers will have the digits 1 and 2 in increasing order? For example, 14352 and 51234 are two such numbers."

Let's start by taking a look with the number 1. There are four possible places 1 could be, because there needs to be space for the 2 after it.

Checkmarks mark where the 1 can be, the <em>x</em> marks where it cannot be.

\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{X}

Let's start with the first position:

\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are four places the 2 can be. For each of these four places, we can arrange the remaining 3 digits in 3!=6 ways. Therefore, there are 4\cdot 6=\boxed{24} possible numbers when 1 is the first digit of the number.

Continue this process with the remaining possible positions for 1.

Second position:

\underline{X}\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are three places the 2 can be, since the 2 must be behind the 1. For each of these three places, the remaining 3 digits can be arranged in 3!=6 ways. Therefore, there are 3\cdot 6=\boxed{18} possible numbers when 1 is the second digit of the number.

The pattern continues. Next there will be 2 places to place the 2. For each of these, there are 3!=6 ways to rearrange the remaining 3 digits for a total of 2\cdot 6=\boxed{12} possible numbers when 1 is the third digit of the number.

Lastly, when 1 is the fourth digit of the number, there is only 1 place the 2 can be. For this one place, there are still 3!=6 ways to rearrange the remaining three numbers. Therefore, there are 1\cdot 6=\boxed{6} possible numbers when 1 is the fourth digit of the number.

Thus, there are 24+18+12+6=\boxed{60} numbers that will have the digits 1 and 2 in increasing order, from a set of 120 five-digit numbers created by the digits 1 through 5, where no digit may be repeated.

5 0
3 years ago
What is 120 divided by20
anzhelika [568]

Answer:

5

Step-by-step explanation:

120/20=5

6 0
3 years ago
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