<u>Answer:
</u>
The solution of
for M = 10, N = -5P and P = -2 is 25
<u>Solution:
</u>
From question, given that the value of M is 10 and N is -5p and P is -2
We have to evaluate the value of
,
By substituting the values of M and N, we get
![\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7BM%5E%7B2%7D%7D%7BP%5E%7B2%7D%7D%20%3D%20%5Cfrac%7B10%5E%7B2%7D%7D%7B%28-2%29%5E%7B2%7D%7D)
Expanding
:
Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.
![10^{2} = 10 \times 10 = 100](https://tex.z-dn.net/?f=10%5E%7B2%7D%20%3D%2010%20%5Ctimes%2010%20%3D%20100)
Similarly expanding
:
Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.
![(-2)^{2} = -2 \times -2 = 4](https://tex.z-dn.net/?f=%28-2%29%5E%7B2%7D%20%3D%20-2%20%5Ctimes%20-2%20%3D%204)
So the equation
becomes,
![\frac{M^{2}}{P^{2}} = \frac{100}{4}](https://tex.z-dn.net/?f=%5Cfrac%7BM%5E%7B2%7D%7D%7BP%5E%7B2%7D%7D%20%3D%20%5Cfrac%7B100%7D%7B4%7D)
By dividing 100 by 4 , we get the result as 25
Hence the solution of
when M = 10 and P = -2 is 25
Answer:
<h3>
Triangle CBB1 and Triangle CAA1 are similar and line B to B1 and line A to A1 are proportional.</h3>
Step-by-step explanation:
You would earn $34 in total because 3x3 equals 9. And 12+5+7=24. 9+24÷35
Answer: -16x^6 - 6x + 17
Step-by-step explanation: Simplify the expression.
I hope this helps you out. :)
Answer:
Step-by-step explanation:
- Use of low <em>of sines</em>
- <em>Consider triangle CEN</em>
- <em>Bearing of angle counted from zero to the vector of flight</em>
<u>We have </u>
- ∠CNE = complementary with 44° ⇒ m∠CNE = 90° - 44° = 46°
- NE = b = 545 km
- EC = a = 680 km
- ∠ECN = x
<u>Find the measure of angle x:</u>
- sin 46° / a = sin x / b
- sin 46° / 680 = sin x / 545
- sin x = 545 sin 46 deg / 680
- x = arcsin (545 sin 46 deg / 680)
- x = 35° (rounded)
<u>Bearing of the flight from Elgin to Canton is:</u>
- 270° - 35° = 235° as the vector is in the third quadrant