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3 years ago

7

Need help fast Yesterday's afternoon temperature was 21°F. It plunged overnight to -3°F. How many degrees did the temperature dr

op?
A) 3°
B) 18°
C) 21°
D) 24°

1 answer:

Nezavi [6.7K]3 years ago

6 0

The Answer to all the questions are D C D D B

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Simplfy <br> -3+(-10) <br> please explain how to do it too because i am lost in algebra.

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2 years ago

You and three friends are planning a trip. You want to keep the cost below $90 per person. Write and solve an inequality that re

velikii [3]

Answer: x < 360

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Let x be the total cost for the trip.

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3 years ago

Mrs. Walters drove 360 miles on 25 gallons of gas. Mr. Walters drove 480 miles on 32 gallons of gas.

Temka [501]

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480:32

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3 years ago

Read 2 more answers

A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui

Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= $\frac{dx}{dt}=1. 8 m/s$

$\triangle ABD\sim\triangle ECD$

Therefore, $\frac{AB}{EC}=\frac{BD}{CD}$

$\frac{y}{2}=\frac{12}{x}$

$xy=24$

Differentiate w.r.t t

$x\frac{dy}{dt}+y\frac{dx}{dt}=0$

$x\frac{dy}{dt}=-y\frac{dx}{dt}$

$\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}$

When the man is 4 m from the building

Then, we have x=12-4=8 m

$\frac{dx}{dt}=1.8 m/s$

Substitute the values in above equation then, we get

$8y=24$

$y=\frac{24}{8}=3$

Substitute the values then we get

$\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s$

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0

3 years ago