D= sqrt( (6-4)^2 + (5sqrt2 - 3sqrt2)^2 )
It's d= 3,46 i think
Answer:
1668 feet.
Step-by-step explanation:
We know the opposite side of the right triangle and we need the adjacent side, so we use the tangent function.
If the distance required is x (adj side) we have:
tan 41 = opp/adj
tan 41 = 1450/x
x = 1450 / tan 41
= 1668.03
Over this 10-minute interval, the car's average acceleration is

The MVT says that at some point during this 10-minute interval, the car must have had an acceleration of 60 mi/h^2.
F(a+h)=2(a+h)³=2(a³+3a²h+3h²a+h³)
the second choice is the correct answer.