Question

A 10-gram aluminum cube absorbs 677 joules when its temperature is increased from 50°c to 125°

Answer 1

Answer : The specific heat of aluminum is, $0.90J/g^oC$

Solution : Given,

Heat absorbs  = 677 J

Mass of the substance = 10 g

Final temperature = $125^oC$

Initial temperature = $50^oC$

Formula used :

$Q= m\times c\times \Delta T$

or,

$Q= m\times c\times (T_{final}-T_{initial})$

Q = heat absorbs

m = mass of the substance

c = heat capacity of aluminium

$T_{final}$ = final temperature

 $T_{initial}$ = initial temperature

Now put all the given values in the above formula, we get the specific heat of aluminium.

$677g= (10g)\times c\times (125-50)^oC$

$c=0.9026J/g^oC=0.90J/g^oC$

Therefore, the specific heat of aluminum is, $0.90J/g^oC$

Answer 2

0.90 is the correct answer