A particle moves along the x-axis according to x(t)=10t−2t²m. (a) What is the instantaneous velocity at t = 2 s and t = 3 s? (b)
1 answer:
Answer:
a) v(2) = 2m/s, v(3) = -2m/s
b) speed at t = 2s is 2m/s
speed at t = 3s is 2m/s
c) 0 m/s
Explanation:
We can take the derivative of x(t) to find the equation of velocity
v(t) = x'(t) = 10 - 4t
(a) v(2) = 10 - 4*2 = 10 - 8 = 2 m/s
v(3) = 10 - 4*3 = 10 - 12 = -2 m/s
(b) The speed would be the same as velocity without the direction
speed at t = 2s is 2m/s
speed at t = 3s is 2m/s
(c) The average velocity between t = 2s and t = 3s is distance it travels over period of time
You might be interested in
Newton's second law and graphical analysis allow us to find the correct answer for the measure of the constant b is:
D) Stack several filters to change the mass measure the acceleration of the system.
Newton's second law establishes a relationship between the net force, the mass and the acceleration of the bodies.
∑ F = m a
Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.
They indicate that the drag force on the filters is
F = - b v
Where b is a positive constant that depends on the shape and area of the filter and v is the speed of the filter.
Let's write Newton's second law.
W - fr = ma
W -bv = ma
In the experiment the students indicate that they can measure the position, velocity and acceleration of the body.
Based on the above, if we place several filter weights and measure their speed and acceleration in each case, we can make a graph of velocity versus acceleration, we can take the value of the constant b from the slope.
Let's analyze the different answers:
A) False. The constant b depends on the shape of the filter therefore it must be kept constant.
B) False. The constant depends on the area, so it must be kept constant.
C) May be. In this case, since we have the terminal velocity, the acceleration is zero, Newton's second law remains.
B v - W = 0
b =
The problem with the method is the difficulty of measuring the compression terminal velocity.
D) True. According to the discussion of the velocity versus acceleration. graph, the constant b is equal to the slope of the graph.
E) May be. The problem with this method is finding a reliable value for the terminal velocity.
In conclusion, using Newton's second law and graphical analysis we can find the correct answer for the measure of the constant b is:
D) Stack several filters to change the mass measure the acceleration of the system.
Learn more here: brainly.com/question/2441565
Answer:
1.98 atm
Explanation:
Given that:
Temperature = 28.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (28 + 273.15) K = 301.15 K
n = 1
V = 0.500 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L atm/ K mol
Applying the equation as:
P × 0.500 L = 1 ×0.0821 L atm/ K mol × 301.15 K
⇒P (ideal) = 49.45 atm
Using Van der Waal's equation
R = 0.0821 L atm/ K mol
Where, a and b are constants.
For Ar, given that:
So, a = 1.345 atm L² / mol²
b = 0.03219 L / mol
So,
⇒P (real) = 47.47 atm
Difference in pressure = 49.45 atm - 47.47 atm = 1.98 atm