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3 years ago

Can someone please help me and write the answers? i need this and it’s really important!!

Physics

1 answer:

eduard3 years ago

5 0

-- Kinetic energy is the energy of mass in motion. The amount is determined by the mass of whatever is moving, and its speed.

-- Potential energy is the energy that's stored up in some form, not being used yet but ready to be used when you want it.

For example, one form of it is chemical potential energy, like in a battery, or a match. You get the energy out of a battery when you connect it to a motor or a light. You get the energy out of as match when you make the tip hot and it flares up.

This question is asking about gravitational potential energy. An object has stored energy just by being up high, like a bowling ball on a shelf. You get the energy out of it just by dropping it ... possibly enough to crack the floor !

The amount of this kind of potential energy is determined by the mass of the object, and how high up it is.

-- Getting the answers from other people doesn't help you a bit, until you understand them and can answer the question on your own.

You might be interested in

A current I flows down a wire of radius a.

Helga [31]

Answer:

(a) $K = \frac{I}{2\pi a}$

(b) $J = \frac{I}{2\pi as}$

Explanation:

(a) The surface current density of a conductor is the current flowing per unit length of the conductor.

$K = \frac{dI}{dL}$

Considering a wire, the current is uniformly distributed over the circumferenece of the wire.

$dL = 2\pi r$

The radius of the wire = a

$dL = 2\pi a$

The surface current density $K = \frac{I}{2\pi a}$

(b) The current density is inversely proportional

$J \alpha s^{-1}$

$J = \frac{k}{s}$ ......(1)

k is the constant of proportionality

$I = \int\limits {J} \, dS$

$I = J \int\limits \, dS$ ........(2)

substituting (1) into (2)

$I = \frac{k}{s} \int\limits\, dS$

$I = k \int\limits^a_0 \frac{1}{s} {s} \, dS$

$I = 2\pi k\int\limits\, dS$

$I = 2\pi ka$

$k = \frac{I}{2\pi a}$

substitute $J = \frac{k}{s}$

$J = \frac{I}{2\pi as}$

7 0

3 years ago

2. Three blocks, A,B and C of mass 2kg. 3kg. 5kg respectively kept side by side with one another are accelerated at 2m/s2 across

gulaghasi [49]

Answer:

Total mass of combination = 2+3+5 = 10kg.

Acceleration produced = 2m/s^2

hence force =( total mass × acceleration)= (2×10)= 20 N.

Net force on 3kg block = acceleration × mass = (2 × 2 )= 4 N

applied force on 2 kg block = 20N

Force between 2 kg and 3 kg block = (20-4) = 16N. ans

Net force on 3 kg block = 3 × 2 =6N.

Applied force on 3 kg block due to 2 kg block = 16N.

hence, force between 3 kg and 5 kg block = (16-6) = 10N .

answers:-

(a) 20 N

(b) 16N

4 0

1 year ago

Which of the following could be the source of resistance in a household electric circuit?

Tpy6a [65]

D. all of these

all of these use electricity

Hope I helped!

8 0

3 years ago

Read 2 more answers

2. a) Force affects the body and results in different changes. The grid given below

postnew [5]

Answer:

Please find the answer in the explanation

Explanation:

Given that Force affects the body and results in different changes.

The grid that has the words related to the effects of force are :

a) Force could be a push or a pull.

c) Force has magnitude as well as direction.

e) Force acting on an object may cause a change in its state of motion or a change in its shape.

f) A force can act on an object with or without being in contact with it.

8 0

3 years ago

For the following types of electromagnetic radiation, how do the wavelength, frequency, and photon energy change as one goes fro

KIM [24]

Answer:

Wavelength, frequency and the photon energy changes as the one goes across the ranges of the electro-magnetic radiations.

Explanation:

Electro-magnetic radiations may be defined as the form of energy that is radiated or given by the electro-magnetic radiations. The visible light that we can see is the one of the electro-magnetic radiations. Other forms are the radio waves, gamma waves, UV rays, infrared radiations, etc.

The wavelength of the radiations decreases as we go from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.

The frequency of the radiations increases when we move from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.

The photon energy of the radiations increases when we move from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.

5 0

3 years ago