Answer:
a. The horizontal component of acceleration a₁ = 0.68 m/s²
The vertical component of acceleration a₂ = -0.11 m/s²
b. -9.19° = 350.81° from the the positive x-axis
Explanation:
The initial velocity v₁ of the fish is v₁ = 4.00i + 1.00j m/s. Its final velocity after accelerating for t = 19.0 s is v₂ = 17.0i - 1.00j m/s
a. The acceleration a = (v₂ - v₁)/t = [17.0i - 1.00j - (4.00i + 1.00j)]/19 = [(17.0 -4.0)i - (-1.0 -1.0)j]/19 = (13.0i - 2.0j)/19 = 0.68i - 0.11j m/s²
The horizontal component of acceleration a₁ = 0.68 m/s²
The vertical component of acceleration a₂ = -0.11 m/s²
b. The direction of the acceleration relative to the unit vector i,
tanθ = a₂/a₁ = -0.11/0.68 = -0.1618
θ = tan⁻¹(-0.1618) = -9.19° ⇒ 360 + (-9.19) = 350.81° from the the positive x-axis
B. A film of food wrap. The cell membrane is the outermost layer that is protecting the cell
Answer:
20 mA
Explanation:
We have given that the transformer convert 120 V to 12 V means it is a step down transformer
The turn ratio of the transformer is given as
here
is primary voltage and
is secondary voltage
As the voltage decreases from primary to secondary so current will increase from primary to secondary
We have given output current that is secondary current so primary that is input current will be less
So input current
Answer:
The answer is C. Steer in a straight line while gently slowing down
Explanation:
The following are advised when your cars go off the pavement while driving;
firstly, Do not panic.
ensure you hold on to your steering wheel tightly.
keep Steering straight ahead.
ensure you Stay on the shoulder.
Ease up on the accelerator and brake gently.
When you know you can safely do so, turn back on the road at a much lower speed.