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3 years ago

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a wheel of mass 38kg is lifted to a height of 0.8m .how much gravitional potential energy is added to the wheel? accélération du

e to gravity is g=9.8m/s

1 answer:

White raven [17]3 years ago

4 0

297.92J of GPE is added.

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S ship maneuvers to within 2.50x10^3 m of an islands 1.80x10^3 m high mountain peak and fires a projectile at an enemy ship 6.10

lilavasa [31]

velocity of the projectile is given as

$v = 2.50 \times 10^3 m/s$

now the angle is given as 75 degree

so here we will have

$v_x = 2.50 \times 10^3 cos75 = 0.65 \times 10^3 m/s$

$v_y = 2.50 \times 10^3 sin75 = 2.4 \times 10^3 m/s$

now the time taken to reach the peak is given as

$t = \frac{x}{v_x}$

$t = \frac{2.50 \times 10^3}{0.65 \times 10^3} = 3.86 s$

now the height moved by the projectile in same time is given as

$y = v_y t + \frac{1}{2}at^2$

now we have

$y = (2.4 \times 10^3)(3.86) - \frac{1}{2}(9.81)(3.86)^2$

$y = 9.2 \times 10^3 m$

so distance between the peak and projectile is given as

$d = 9.2 \times 10^3 - 1.80 \times 10^3 = 7.4 \times 10^3 m$

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3 years ago

What is rotational speed

arlik [135]

The number of turns of the object divided by time

5 0

4 years ago

Read 2 more answers

The graph below show how natural processes and human activities affect climate

Kaylis [27]

Is it just me or can anyone else not see a graph? (Because I can’t)

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4 years ago

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Describe at least two ways that electromagnet force and weak nuclear forces are alike and two ways that they are different.

ruslelena [56]

Different: The weak nuclear force is responsible for radioactive decay within an atom of a substance, while the electromagnetic force causes electrostatic force between charged particles.

Different: The weak force has a very small range of effectiveness (where the force can be felt) while the electromagnetic force has an infinite range.

Same: Both forces act within an nucleus, or on a nuclear level.

Same: The weak nuclear force is mediated by charged particles called bosons, and the electrostatic force is only present within charged objects

The last one may be a bit of a stretch but I hope this helped a bit!

4 0

4 years ago

Consider a positive charge Q and a point B twice as far away from Q as point A. What is the ratio of the electric field strength

Vikentia [17]

Answer:

$\frac{E_{A}}{E_{B}}=4$

Explanation:

The electric field is defined as the electric force per unit of charge, this is:

$E=\frac{F}{q}$ .

The electric force can be obtained through Coulomb's law, which states that the electric force between to electrically charged particles is inversely proportional to the square of the distance between them and directly proportional to the product of their charges. The electric force can be expressed as

$F=\frac{kQq}{r^{2}}$ .

By substitution we get that

$E=\frac{kQq}{qr^{2}}\\\\E=\frac{kQ}{r^{2}}$

Now, letting $E_{A}$ be the electric field at point A, letting $E_{B}$ be the electric field at point B, and letting R be the distance from the charge to A:

$E_{A}=\frac{kQ}{R^{2}}\\\\E_{B}=\frac{kQ}{(2R)^{2}}$ .

The ration of the electric fields is

$\frac{E_{A}}{E_{B}}=\frac{\frac{kQ}{R^{2}}}{\frac{kQ}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(4)R^{2}}}\\\\\\\frac{E_{A}}{E_{B}}=\frac{1}{\frac{1}{(4)}}\\\\\frac{E_{A}}{E_{B}}=4$

This means that at half the distance, the electric field is four times stronger.

4 0

3 years ago