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1 year ago

Will give 15 points and brainliest

Mathematics

2 answers:

yanalaym [24]1 year ago

6 0

Answer:

the answer is A 1390

pentagon [3]1 year ago

4 0

Answer:

1331π cm³

Explanation:

$\sf V_{cylinder} = \pi (radius)^2 (height)$

Here given:

radius: 11 cm
height: 11 cm

Hence find volume:

$\sf \rightarrow\pi (11)^2 (11)$

$\sf \rightarrow 121\pi ( (11)$

$\sf \rightarrow 1331\pi \quad \approx \:\:\ 4181.46 \ cm^3$

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If a wagon wheel has a diameter of 70cm, how many revolutions would it take to travel 66 METERS?

ddd [48]

Answer:

30 revolutions

Step-by-step explanation:

to calculate the revolution of the wheels in 66 metres we need to get the circumference

circumference = 2πr, r = radius (diameter divided by 2) but from the formula of circumference we ca rewrite it as πd= 3.14 x 70 = 219.8cm

next convert 66 metres to cm

100cm = 1m

x= 66m

cross multiply

x= 66m x100cm/1m= 6600cm

revolutions in 66metres = 6600cm/219.8cm = 30.0272975 ≅30 revolutions

6 0

3 years ago

A science teacher showed an image of a carpenter bee on a wall. The image is 10 times as large as the actual bee.

Fudgin [204]

PLease state ure question if the bee is on a wall.Whaat size is the bee?

4 0

3 years ago

Please help thank you. i have 2 questions.

Alenkinab [10]

For the first one, the answer is 2. You can only fold it vertically and horizontally. For the second one, the answer is O because any way you turn it, it still looks like O. I hope this helps!

3 0

3 years ago

Read 2 more answers

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0

2 years ago

H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?

zubka84 [21]

$H(x)=(x^2)+1\ \ \ \ and\ \ \ \ K(x)=-(x^2)+4. \\\\K(H)=-(H^2)+4=-(x^2+1)^2+4=4-(x^2+1)^2=\\\\.\ \ \ =2^2-(x^2+1)^2=(2-x^2-1)(2+x^2+1)=(1-x^2)(3+x^2)=\\\\.\ \ \ =(1-x)(1+x)(x^2-3\cdot i^2)=(1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)\\\\ K(H)=0\ \ \ \ \Leftrightarrow\ \ \ (1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)=0\\\\x=1\ \ \ \ or\ \ \ \ x=-1\ \ \ \ or\ \ \ \ x=\sqrt{3} \cdot i\ \ \ \ or\ \ \ \ x=-\sqrt{3} \cdot i\\\\Ans.\ e.$

4 0

3 years ago