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babymother [125]
1 year ago
7

Will give 15 points and brainliest

Mathematics
2 answers:
yanalaym [24]1 year ago
6 0

Answer:

the answer is A 1390

pentagon [3]1 year ago
4 0

Answer:

 1331π cm³

Explanation:

\sf V_{cylinder} = \pi (radius)^2 (height)

Here given:

  • radius: 11 cm
  • height: 11 cm

Hence find volume:

\sf \rightarrow\pi (11)^2 (11)

\sf \rightarrow 121\pi ( (11)

\sf \rightarrow 1331\pi \quad \approx \:\:\ 4181.46 \ cm^3

You might be interested in
One pumpkin weighs 7 lb 12 oz. A second pumpkin with 10 pounds 4 ounces. A pumpkin weighs 2 pounds 9 ounces more than the second
Nesterboy [21]

Answer:  30 lbs, 13 oz

This converts to 493 ounces

===============================================================

Explanation:

Pumpkin A weighs 7 lb, 12 oz. Let's convert that to ounces only

1 lb = 16 oz

7 lbs = 112 oz (multiply both sides by 7)

7 lbs, 12 oz = 112 oz + 12 oz .... add 12 oz to both sides

7 lbs, 12 oz = 124 oz

Pumpkin A's weight of 7 lbs, 12 oz is the same as 124 oz

-----------

Do something similar for pumpkin B

1 lb = 16 oz

10 lbs = 160 oz

10 lbs, 4 oz = 160 oz + 4 oz

10 lbs, 4 oz = 164 oz

Pumpkin B weighs 164 oz

-----------

Let's convert the "2 lbs, 9 oz" to ounces only

1 lb = 16 oz

2 lbs = 32 oz

2 lbs, 9 oz = 32 oz + 9 oz

2 lbs, 9 oz = 41 oz

So pumpkin C is 41 ounces heavier compared to pumpkin B

The weight of pumpkin C is 164+41 = 205 ounces

----------

We have these three weights in ounces only

  • Pumpkin A = 124 oz
  • Pumpkin B = 164 oz
  • Pumpkin C = 205 oz

Adding those three ounces only weights leads to

124+164+205 = 493 ounces

The total weight of all three pumpkins is 493 ounces

Now let's convert back to the unit "pounds, ounces"

Divide that result over 16 since there are 16 ounces per pound

493/16 = 30.8125

Ignore the decimal portion. The 30 is the quotient which means 493-30*16 = 13 is the remainder.

In other words,

493/16 = 30 remainder 13

which leads to

493 ounces = 30 pounds, 13 ounces

--------------

As a check,

1 lb = 16 oz

30 lbs = 480 oz

30 lbs, 13 oz = 480 oz + 13 oz

30 lbs, 13 oz = 493 oz

The answer is confirmed.

8 0
2 years ago
The total weight of 30 bags of flour and 4 bags of sugar is 42.6 kg. if each bag of sugar weighs 0.75 kg, what is the weight of
slavikrds [6]
X = weight of each bag of flour

30x + 4*0.75 = 42.6
30x + 3 = 42.6
30x = 39.6
x = 39.6/30
x = 1.32kg
8 0
3 years ago
Read 2 more answers
Please help, thanks. I don't understand how to do this.​
konstantin123 [22]

Answer:

3m(a-2b)+(a-2b)^2

= 3m(a-2b)+(a-2b)(a-2b)

= (a-2b)(3m+a-2b)

6 0
3 years ago
This should be easy for you <br> Please help me
Alik [6]

Explanation:

a. The line joining the midpoints of the parallel bases is perpendicular to both of them. It is the line of symmetry for the trapezoid. This means the angles and sides on one side of that line of symmetry are congruent to the corresponding angles and sides on the other side of the line. The diagonals are the same length.

__

b. We observe that adjacent pairs of points have the same x-coordinate, so are on vertical lines, which have undefined slope. KN is a segment of the line x=1; LM is a segment of the line x=3. If the trapezoid is isosceles, the midpoints of these segments will be on a horizontal line. The midpoint of KN is at y=(3-2)/2 = 1/2. The midpoint of LM is at y=(1+0)/2 = 1/2. These points are on the same horizontal line, so the trapezoid <em>is isosceles</em>.

__

c. We observed in part (b) that the parallel sides are KN and LM. The coordinate difference between K and L is (1, 3) -(3, 1) = (-2, 2). That is, segment KL is the hypotenuse of an isosceles right triangle with side lengths 2, so the lengths of KL and MN are both 2√2.

_____

For part (c), we used the shortcut that the hypotenuse of an isosceles right triangle is √2 times the leg length.

7 0
3 years ago
The diameters of ball bearings are distributed normally. The mean diameter is 107 millimeters and the population standard deviat
tensa zangetsu [6.8K]

Answer:

0.6710

Step-by-step explanation:

The diameters of ball bearings are distributed normally. The mean diameter is 107 millimeters and the population standard deviation is 5 millimeters.

Find the probability that the diameter of a selected bearing is between 104 and 115 millimeters. Round your answer to four decimal places.

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 107 mm

σ is the population standard deviation = 5 mm

For x = 104 mm

z = 104 - 107/5

z = -0.6

Probability value from Z-Table:

P(x = 104) = 0.27425

For x = 115 mm

z = 115 - 107/5

z = 1.6

Probability value from Z-Table:

P(x = 115) = 0.9452

The probability that the diameter of a selected bearing is between 104 and 115 millimeters is calculated as:

P(x = 115) - P(x = 104)

0.9452 - 0.27425

= 0.67095

Approximately = 0.6710

8 0
3 years ago
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