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1 year ago

Will give 15 points and brainliest

Mathematics

2 answers:

yanalaym [24]1 year ago

6 0

Answer:

the answer is A 1390

pentagon [3]1 year ago

4 0

Answer:

1331π cm³

Explanation:

$\sf V_{cylinder} = \pi (radius)^2 (height)$

Here given:

radius: 11 cm
height: 11 cm

Hence find volume:

$\sf \rightarrow\pi (11)^2 (11)$

$\sf \rightarrow 121\pi ( (11)$

$\sf \rightarrow 1331\pi \quad \approx \:\:\ 4181.46 \ cm^3$

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Find the unknown length of the right triangle. If necessary approximate the length to the nearest thousandth

WARRIOR [948]

We are given a right triangle and we are asked to determine the hypotenuse given the measure of its sides. To do that we will use the Pythagorean theorem:

$h^2=(10km)^2+(20km)^2$

Now, we solve the square:

$h^2=100km^2+400km^2$

Now, we add the values:

$h^2=500km^2$

Now, we take the square root to both sides:

$h=\sqrt[]{500km^2}$

Solving the operations:

$h=22.361km$

Therefore, the length of the hypotenuse is 22.361 kilometers.

6 0

1 year ago

Help a uneducated sis out✊

N76 [4]

Answer & Step-by-step explanation:

The domain of a set of points refers to the input, also known as the x values. To find the domain, record all the x values given (x,y):

$domain={-2,0,3,5}$

:Done

**The range is the output, aka the y values.

5 0

2 years ago

Review: Angle Bisectors

zmey [24]

Answer:

m∠AOC = 15°

m∠BOC = 15°

Step-by-step explanation:

Given the angle ∠AOB

It is stated that CO is the angle bisector of ∠AOB.

Given that ∠AOB = 30°

As we know that the angle bisector bisects the angle into two equal angles.

Thus, the angle bisector CO bisects the angle ∠AOB into two equal angles, which are:

m∠AOC

m∠BOC

∠AOB = 30°

Thus, the two formed angles i.e m∠AOC and m∠BOC by the angle bisector would be half of the angle bisector as the angle bisector bisects the angle ∠AOB into two equal angles.

Therefore,

m∠AOC = 15°

m∠BOC = 15°

7 0

3 years ago

Which is the solution set to the inequality (4x-3)(2x-1)&gt=0?

Serjik [45]

(4x - 3)(2x - 1) ≥ 0

First, find the zeros:

4x - 3 = 0 2x - 1 = 0

x = $\frac{3}{4}$ x = $\frac{1}{2}$

Next, plot these points and choose test points on the outside and between the zeros:

←-------0------ $\frac{1}{2}$ ------ $\frac{5}{8}$ ------ $\frac{3}{4}$ ------1------→

Lastly, plug in the test points and look for a positive result (since it is greater than 0).

Test Point 0: [4(0) - 3][2(0) - 1] = ( - )( - ) = + THIS WORKS!

Test Point $\frac{5}{8}$ : [4( $\frac{5}{8}$ ) - 3][2( $\frac{5}{8}$ ) - 1] = ( - )( + ) = - This does NOT work

Test Point 1: [4(1) - 3][2(1) - 1] = ( + )( + ) = + THIS WORKS!

Answer: x ≤ $\frac{1}{2}$ or x ≥ $\frac{3}{4}$

Interval Notation: (-∞, $\frac{1}{2}$ ] U [ $\frac{3}{4}$ , ∞)

Graph: ←------ $\frac{1}{2}$ $\frac{3}{4}$ --------→

5 0

3 years ago

Given: SP = PT = ST = 2.6 MO⊥ (SPT) m∠MPO = 70º Find: Volume

ohaa [14]

Answer:

Step-by-step explanation:

Volume = 1/3(area of triangular base)height

To find the triangular base we would use heron formula Area = square root (s-a)(s-b)(s-c)

S = (a+b+c)/2 = 2.6 + 2.6 + 2.6 )/2

4 0

3 years ago