Answer:
x = - 9
Step-by-step explanation:
Given g(x) = - x - 3 and g(x) = 6, then equate, that is
- x - 3 = 6 ( add 3 to both sides )
- x = 9 ( multiply both sides by - 1 )
x = - 9
Answers for A:
Factored form: (x-2)(x+4)
Zeros: x = 2, -4
Vertex: (-1, -9)
Answers for B:
Factored form: -(x+2)(x+7)
Zeros: x = -2, -7
Vertex: (-9/2, 25/4)
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
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Step-by-step explanation:
