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Rashid [163]
3 years ago
5

Im really stuck on this............

Mathematics
2 answers:
Ivenika [448]3 years ago
4 0

Answer:

H, 13

Step-by-step explanation:

Distance formula:

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\sqrt{(7-(-5))^2+(-5-0)^2}\\\sqrt{144+25}\\\sqrt{169}\\13

Len [333]3 years ago
3 0

Answer:

H is the Answer

Step-by-step explanation:

Apply distance formula.

(x {}^{2  } -  {x}^{1}  ) {}^{2}  + ( {y}^{2}  -  {y}^{1} ) {}^{2}  = d {}^{2}

where d is the distance.

( - 5 - 7) {}^{2}  + (0 - 5) {}^{2}  =

- 12 {}^{2}  +  - 5 {}^{2}  =  {d}^{2}

\sqrt{169}  =  {d}^{2}

d = 13

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How do I solve this with Substitution?
TiliK225 [7]
They give you an "x =" statement so you plug in the right side of the equals sign into the first equation wherever x appears. So...

y = 10 - 2(y - 4)
y = 10 - 2y + 8
y = 18 - 2y
y + 2y = 18
3y = 18
y = 6

Now we plug in this result for the y-value into the "x =" statement.

x = 6 - 4
x = 2

Your answer is (2, 6) 
8 0
3 years ago
HELP PELASE ILL MARK BRAINLIEST AND POINTS!
UNO [17]

\qquad\qquad\huge\underline{{\sf Answer}}

Both the given lines in graph intersect at point (5 , -2), the point must satisfy both the equations.

and if we check the options, we will observe that D. option has both the equations that satisfy the given conditions.

that is ~

\qquad \sf  \dashrightarrow \: x + y = 3

put y = - 2,we will get :

\qquad \sf  \dashrightarrow \: x - 2 = 3

\qquad \sf  \dashrightarrow \: x = 5

so, 1st equation satifys the condition. let's check out 2nd one.

\qquad \sf  \dashrightarrow \: x + 2y = 1

put y = -2

\qquad \sf  \dashrightarrow \: x + (2 \times  - 2) = 1

\qquad \sf  \dashrightarrow \: x - 4 = 1

\qquad \sf  \dashrightarrow \: x = 5

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5 0
2 years ago
What is the equation for the points (-9,7) and (-6,-3)
andriy [413]

In point slope form, the equation is y-7=(-10/3)(x+9).  In slope-intercept form, it is y=(-10/3)x-23.

First find the slope of the line.  The formula for slope is

m=(y₂-y₁)/(x₂-x₁)

Using our points, we have  

m=(-3-7)/(-6--9) = -10/3

Plug this into point slope form:

y-y₁=m(x-x₁)

y-7=(-10/3)(x--9)

y-7=(-10/3)(x+9)

Using the distributive property:

y-7=(-10/3)*x+(-10/3)*9

y-7=(-10/3)x-90/3

y-7=(-10/3)x-30

Add 7 to both sides:

y=(-10/3)x-23

4 0
3 years ago
Please help asap thank you so much
Kryger [21]

Answer:

1) x = 6.6.

2) x = 6.1.

Step-by-step explanation:

1) In this triangle, the hypotenuse is given, which is 8 units, and the angle is given, which is 35 degrees. The base is unknown. To find the base, following ratio will be used:

cos θ = Base/Hypotenuse.

cos 35 = x/8.

x = 8*cos 35.

x = 6.6 units (to the nearest tenth)!!!

2) In this triangle, the base is given by 12, and the angle is given by 27 degrees. The perpendicular is unknown. To find the perpendicular in this case, tangent formula will be used:

tan θ = Perpendicular/Base

tan 27 = x/12.

x = 12*tan 27.

x = 6.1 units (to the nearest tenth)!!!

8 0
4 years ago
Read 2 more answers
X+7y=-9 solve.<br> x=97+23
Oksi-84 [34.3K]

Answer:

1. x=-9-7y

2. x = 120

Step-by-step explanation:

8 0
3 years ago
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