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klemol [59]
3 years ago
10

A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6

days after inoculation?
Mathematics
1 answer:
ddd [48]3 years ago
3 0

Answer:

The population of bacteria after 6 days is 2,313.06

Step-by-step explanation:

Given as :

The initial population of bacteria = i = 1,000 bacteria

The growth rate of bacteria per day = 15%

Let The population of bacteria after 6 days = f

The time period of growth = 6 days

<u>Now, According to question</u>

The population of bacteria after 6 days = initial population × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, f = i × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, f = 1000 × (1+\dfrac{\textrm 15}{100})^{\textrm 6}

Or, f = 1000 × (1.15)^{6}

Or, f = 1000 × 2.31306

∴  f = 2,313.06

So,The population of bacteria after 6 days = f = 2,313.06

Hence,The population of bacteria after 6 days is 2,313.06  Answer

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Answer:

The generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°

Step-by-step explanation:

We are given the following from what she knows

m∠3=2⋅m∠1... 1

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From what is given, we can substitute equation 1 and 2 into equation 3 as shown:

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m∠2+m∠3=360

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Divide both sides by 2

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Since the sum of two supplementary angles is 180°, hence the generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°

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