1. solutions are intersection points
they intersect at x=4 and x=1 or the points (4,0) and (1,0)
select 4 and 1
2.
sub -x for x
if you get the same function, it is even
if you get the exact negative of the function, it is odd
if neither, then neither
basically
f(-x)=f(x) is even
f(-x)=-f(x) is odd
and neither is neighter
so
f(-x)=-2(-x)²+3(-x)
f(-x)=-2(x)²-3x
f(-x)=-2x²-3x
that is not the same function nor is it the exact oposite
neither even nor odd
3.
domain is the time you can use
obvioulsy start at time=0
and stop when it hits the ground because it shouldn't go underground
so domain is all real numbers from 0 to 5 including 0 and 5
that is [0,5]
4. (the (f+g)(x) one)
(f+g)(x)=f(x)+g(x)
so that is just
x²-36+x³+2x²-10=
x³+3x²-46
5. just mulitply them
x⁷+9x⁴-9x³-81
6. minus them
(3x⁵+6x²-5)-(2x⁴+7x²-x+16)
3x⁵+6x²-5-2x⁴-7x²+x-16
3x⁵-2x⁴-x²+x-21
Answer:
1 3 6 10 15
Step-by-step explanation:
brainliest plz
2x^2 if x=1/8 is 1/16
4x^2 if x=1/8 is 1/2
The answer is: 45 * 10 ⁻¹¹ .
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Explanation:
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Given: (9 * 10⁻⁵) * (5 *10 ⁻⁶) ; Simplify.
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(9 * 10⁻⁵) * (5 *10⁻⁶) =
9 * 5 * 10⁻⁵ * 10⁻⁶ =
(9 * 5) * 10⁻⁵ * 10⁻⁶
45 * 10⁻⁵ * 10⁻⁶ ;
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Note the following property of exponents:
xᵃ * xᵇ = x⁽ᵃ⁺ᵇ⁾ ;
As such, 10⁻⁵ * 10⁻⁶ = 10⁽⁻⁵ ⁺ ⁻⁶) = 10 ⁻¹¹ ;
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So; 45 * 10⁻⁵ * 10⁻⁶
= 45 * 10⁻¹¹ .
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Answer:
C
Step-by-step explanation:
Calculate AC using Pythagoras' identity in ΔABC
AC² = 20² - 12² = 400 - 144 = 256, hence
AC = 
= 16
Now find AD² from ΔACD and ΔABD
ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²
ΔABD → AD² = 12² - x² = 144 - x²
Equate both equations for AD², hence
256 - 400 + 40x - x² = 144 - x²
-144 + 40x - x² = 144 - x² ( add x² to both sides )
- 144 + 40x = 144 ( add 144 to both sides )
40x = 288 ( divide both sides by 40 )
x = 7.2 → C
