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Minchanka [31]
4 years ago
5

Write an equation of the circle graphed below

Mathematics
2 answers:
dezoksy [38]4 years ago
5 0

Answer:

(-1,1)

Step-by-step explanation:

erik [133]4 years ago
4 0

Answer:

(x+1)^2+(y-1)^2=1.5625

Step-by-step explanation:

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What is square root of 81
Doss [256]
The square root of 81 is 9, this can be proven by squaring 9, which's result is 81.
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Please help? <br> Find measure of angle C
Lelu [443]

Answer:

82

Step-by-step explanation:

Im pretty sure the answer is 82 as it's a striaght line and all you have to do is subtract 180-98

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3 years ago
The diagram shows the diffrence between my home h and two towns
katrin2010 [14]

Answer:

  • from home to town A :

V = D/t = 10 / 20 = 0.5 mile per min

  • from home to town B :

V = D/t = 20/30 = (2/3) mile per min

  • From town A to town B :

V = D/t = (10+20)/ 50 = (3/5) mile per min

6 0
3 years ago
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Find Mx, My, and (x, y) for the lamina of uniform density rho bounded by the graphs of the equations. y = x2/3, y = 0, x = 1
erik [133]

Answer:

\mathbf{(\overline x , \overline y ) = (\dfrac{5}{8},  \dfrac{5}{14})}

Step-by-step explanation:

Given that:

y =  x^{2/3} at y = 0 , x = 1

Then:

Area = \int^{1}_{0} x^{2/3} \ dx

Area = \begin {bmatrix} \dfrac{3}{5}x^{5/3} \end {bmatrix} ^1_0

Area = \dfrac{3}{5}

Then:

\overline x = \dfrac{1}{A} \int^b_a x (f(x) -g(x) ) \ dx

\overline x = \dfrac{5}{3} \int^1_0 x (x^{2/3} -0 ) \ dx

\overline x = \dfrac{5}{3} \int^1_0 x^{5/3} \ dx

\overline x = \dfrac{5}{3} \ [\dfrac{3}{8}x^{8/3}]^1_0

\overline x = \dfrac{5}{3} \times \dfrac{3}{8}

\overline x = \dfrac{5}{8}

Similarly;

\overline y = \dfrac{1}{A} \int^b_a \dfrac{1}{2} \begin{bmatrix} (f(x)^)2 - (g(x))^2 \end {bmatrix}  \ dx

\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (f(x^{2/3})^2 -0 \end {bmatrix}  \ dx

\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (x^{4/3} ) \end {bmatrix}  \ dx

\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{1}{2}  (x^{7/3} ) \times \dfrac{3}{7} \end {bmatrix} ^1_0

\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{3}{14}  (x^{7/3} ) \end {bmatrix} ^1_0

\overline y = (\dfrac{5}{3} \times \dfrac{3}{14} )

\overline y = \dfrac{5}{14}

Thus; \mathbf{(\overline x , \overline y ) = (\dfrac{5}{8},  \dfrac{5}{14})}

4 0
3 years ago
Part F What is the mean absolute deviation for Doctor A’s data set on glasses? What is the mean absolute deviation for Doctor B’
frez [133]

There is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset

<h3>The doctors' mean absolute deviation on glasses</h3>

The dataset of doctor A is given as:

643 634 670 658 636 624 641 655 649 629

The dataset of doctor B is given as:

651 625 622 624 631 621 653 647 646 646

Using a statistical calculator, we have:

<u>Doctor A</u>

  • Doctor A: Mean Absolute Deviation (MAD) = 11.28
  • Doctor B: Mean Absolute Deviation (MAD) = 12

Hence, the mean absolute deviation is 11.28 for Doctor A’s and 12 for Doctor B’s data set on glasses

<h3>The variation of the two data</h3>

In a dataset, the larger the mean absolute deviations value, the larger the variation.

By comparison, 12 is greater than 11.28

Hence, there is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset

Read more about mean absolute deviation at:

brainly.com/question/3250070

#SPJ1

7 0
2 years ago
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