The formula for percentage error is:

$\sf{Percentage~ error= \frac{|Approximate ~-~ Actual|}{|Actual|}}$

Ross got the approximate area as 12, while the actual area was 11.8. So, let's plug it in to the formula.

$\sf{Percentage~ error= \frac{|Approximate ~-~ Actual|}{|Actual|}= \frac{|12-11.8|}{|11.8|}= \frac{|0.2|}{|11.8|}= \frac{0.2}{11.8} \approx 0.0169 }$

Multiply 0.0169 by 100 to make it into a percent.

0.0169 * 100 = 1.69%

Ross's percentage error is 1.69%.

4 0

3 years ago

How many gallons of pure water should be added to 10 gallons of a solution containing 15 % juice so that the remaining solution

tiny-mole [99]

<u>Answer:</u>

a. 1.5 gallon of juice in the solution

b. 10 gallon

c. None

d. 10 gallon

<u>Solution: </u>

Let us assume that the w gallons of pure water to be added

so the total solution will be $(10+w)$ gallon