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Margarita [4]
3 years ago
8

Which of the segments below is a secant

Mathematics
2 answers:
emmainna [20.7K]3 years ago
8 0

Answer:

That is B. XY.

Step-by-step explanation:

A secant is a line that intersects the circle at 2 points.

ser-zykov [4K]3 years ago
6 0

Answer:

B

Step-by-step explanation:

A secant is a line which intersects a circle at 2 points

From the diagram this is XY → B

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This morning, the temperature rose 2 degrees in 2/3 of an hour at what rate did the temperature rise per hour
insens350 [35]

Answer:

3 degrees per hour

Step-by-step explanation:

2 degrees in 2/3 of an hour

2/2 = 1

1 degree in 1/3 of an hour

1*3 = 3

3 degrees in 1 hour

5 0
3 years ago
What is the rational number equivalent to 1.28? The 1.28 has a line above the 28
Svetach [21]
<span>the line over the 28 means the 28 repeats forever.
1.282828.... and so on
 let x be the rational number 1.28...
we can use this trick:
100*1.282828....= 128.282828...
(the decimal 28 part repeats) 100x = 128.28...
next: 100x - x = 128.282828... - 1.282828...
the .282828... part will be subtracted away
99x = 127
divide both sides by 99 to get
x= 127/99</span>
8 0
3 years ago
Instructions are in the picture
Phantasy [73]

Answer:

123123 3213123 12312 dasdsd aw dasd sda asdasd

Step-by-step explanation:

3 0
3 years ago
What are the intercepts of y = 4x − 2?
Hitman42 [59]
Finding the intercepts is a very straight-forward process. First set y = 0 and solve the equation for x. That is your y-intercept! Then go back to the original equation and set x = 0 and solve for y. That is your x-intercept! For a linear equation like this there is only one x-intercept. For any "function" y(x) there can by definition be only one y-intercept.
6 0
3 years ago
Read 2 more answers
Please Help !!!
solong [7]
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)

moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g


Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05

N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
5 0
4 years ago
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