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2 years ago

How do you find surface area

Mathematics

1 answer:

Oksana_A [137]2 years ago

5 0

Answer:

look at my explanation

Step-by-step explanation:

Find the area of two sides (Length*Height)*2 sides. Find the area of adjacent sides (Width*Height)*2 sides. Find the area of ends (Length*Width)*2 ends. Add the three areas together to find the surface area

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Determine if the columns of the matrix form a linearly independent set. Justify your answer. Choose the correct answer below. A.

kondaur [170]

Th matrix is missing. The matrix is :

$\begin{bmatrix}1 &-4 &4 \\ -4 &16 & 4 \end{bmatrix}$

Solution :

The column of the matrix are $\begin{bmatrix}1\\ -4\end{bmatrix}$ , $\begin{bmatrix}-4\\ 16\end{bmatrix}$ , $\begin{bmatrix}4\\ 4\end{bmatrix}$

Now each of them are vectors in $IR^2$ . But $IR^2$ has dimensions of 2. But there are 3 column vectors, hence they are linearly dependent.

Therefore, the column of the given matrix does not form the $\text{linearly independent set}$ as the set contains $\text{more vectors}$ than there are entries in each vector.

Therefore, option (D) is correct.

4 0

2 years ago

Find the probability that a point chosen at random will lie in the shaded region.

malfutka [58]

Step-by-step explanation:

In the 1st question

Total boxes = 6

Shaded boxes = 2

Probability = 2/6 = 1/3

5 0

3 years ago

There are infinitely How many pairs of numbers of which the sum of their cube roots is zero give two of these pairs

ivanzaharov [21]

Answer:

Infinite pairs of numbers

1 and -1

8 and -8

Step-by-step explanation:

Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:

$\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y$

Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.

Examples: 1 and -1; 8 and -8; 27 and -27.

8 0

3 years ago

I need help plzzzzzzzzzzzzjdbfhrrhebehdbzzzzzzzzzzzzzzzz

yulyashka [42]

Answer:A

Step-by-step explanation: im not too sure but i think 1-2/5=3/5 which would be red so

4 0

2 years ago

Read 2 more answers

Select all the conditions for which it is possible to construct a triangle. (7.G.1.2) Group of answer choices a. A triangle with

saw5 [17]

Answer:

b, d, e, f

Step-by-step explanation:

Here are the applicable restrictions:

The sum of angles in a triangle is 180°, no more, no less.
The sum of the lengths of the two shortest sides exceeds the longest side.
When two sides and the angle opposite the shortest is given, the sine of the given angle must be at most the ratio of the shortest to longest sides.

a. A triangle with angle measures 60°, 80°, and 80° (angle sum ≠ 180°, not OK)

b. A triangle with side lengths 4 cm, 5 cm, and 6 cm (4+5 > 6, OK)

c. A triangle with side lengths 4 cm, 5 cm, and 15 cm (4+5 < 15, not OK)

d. A triangle with side lengths 4 cm, 5 cm, and a 50° angle across from the 4 cm side (sin(50°) ≈ 0.766 < 4/5, OK)

e. A triangle with angle measures 30° and 60°, and an included 3 cm side length (OK)

f. A triangle with angle measures 60°, 20°, and 100° (angle sum = 180°, OK)

_____

Additional comment

In choice "e", two angles and the side between them are specified. As long as the sum of the two angles is less than 180°, a triangle can be formed. The length of the side is immaterial with respect to whether a triangle can be made.

The congruence postulates for triangles are ...

SSS, SAS, ASA, AAS, and HL

These essentially tell you the side and angle specifications necessary to define a singular triangle. As we discussed above, the triangle inequality puts limits on the side lengths specified in SSS. The angle sum theorem puts limits on the angles when only two are specified (ASA, AAS).

In terms of sides and angles, the HL postulate is equivalent to an SSA theorem, where the angle is 90°. In that case, the angle is opposite the longest side (H). In general, SSA will specify a singular triangle when the angle is opposite the longest specified side, regardless of that angle's measure. However, when the angle is opposite the shortest specified side, the above-described ratio restriction holds. If the sine of the angle is less than the ratio of sides, then two possible triangles are specified.

4 0

2 years ago