Jack can swim 12 laps in 28 minutes. 28 minutes is 4 times greater than the time it took him to swim 3 laps. With 28 minutes he should therefore be able to swim 4 times as many laps. 3 times 4 equals 12
Using linear combination method, the solution to given system of equations are (-7, -15)
<h3><u>Solution:</u></h3>
Linear combination is the process of adding two algebraic equations so that one of the variables is eliminated
Addition is used when the two equations have terms that are exact opposites, and subtraction is used when the two equations have terms that are the same.
<u><em>Given system of equations are:</em></u>
2x - y = 1 ---- eqn 1
3x - y = -6 ------ eqn 2
Subtract eqn 2 from eqn 1
2x - y = 1
3x - y = -6
(-) -------------
-x = 7
<h3>x = -7</h3>
Substitute x = -7 in eqn 1
2(-7) - y = 1
-14 - y = 1
y = -14 - 1 = -15
<h3>y = -15</h3>
Thus the solution to given system of equations are (-7, -15)
9514 1404 393
Answer:
$7.14
Step-by-step explanation:
Let p, d, q represent the numbers of pennies, dimes, and quarters in the collection, respectively.
p + d + q = 45 . . . . . . . . there are 45 coins in the collection
2p +5 = q . . . . . . . . . . . . 5 more than twice the number of pennies
p + 4 = d . . . . . . . . . . . . . 4 more than the number of pennies
Substituting the last two equations into the first gives ...
p +(p +4) +(2p +5) = 45
4p = 36 . . . . . . . . . . . . . subtract 9
p = 9 . . . . . . . . . . . divide by 4
d = 9 +4 = 13
q = 2(9) +5 = 23
The value of the collection is ...
23(0.25) +13(0.10) +9(0.01) = 5.75 +1.30 +0.09 = 7.14
The coin collection is worth $7.14.
I believe the dryer costs $357.50
there's an easy way to solve this
you just divide the given price($585)
by 2 and then to one half add $65
and the answer is 65+292.5=357.5
Answer:
Part A = the middle one
Part B = 4 days
Step-by-step explanation:
1,300 / 4 = 325
325 x 4 = 1,300
