The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
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Answer: 70%
Step-by-step explanation:
Step 1:
Total number of teachers = 63 + 27
= 90
Step 2:
The percentage of the teachers in the meeting were first-year teachers:
(63 ÷ 90) × 100 = 70%
Answer:
100
Step-by-step explanation:
Answer:
7 feet 6 inches
Step-by-step explanation:
5 yards = 15 feet
15 feet = 180 inches
180/2 = 90 inches
90 = 7.5 feet
Or 7 feet and 6 inches
