BRAINLYEST IF CORRECT!!! What is the special feature of the View Side by Side command?
2 answers:
<u> Allows you to see two parts of the same worksheet side by side</u>
<u>Option: B</u>
<u>Explanation:</u>
The View Side by Side command helps to see the two documents side by side in Word. When using this feature, both the documents open at the same time in different windows side by side.
To view this, click the View tab in Word and then click the View side by side button. Now the document opens in two windows with side by side views. This is used to compare the documents. In case, if we want to disable this view, click the 'View Side by Side' button again so that it comes to the normal view.
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Answer:
Here is the C++ program.
#include <iostream> //to use input output functions
using namespace std; // to access objects like cin cout
void chessboard(int N){ // function that takes a number N as parameter generates corresponding board
int i, j;
string black = "B"; // B for black squares
string white = "W"; // W for white squares
for(i=1;i<=N;i++){ //iterates through each column of the board
for(j=1;j<=N;j++){ //iterates through each row of the board
if((i+j)%2==0) // if sum of i and j is completely divisible by 2
cout<<black<<" "; //displays B when above if condition is true
else //if (i+j)%2 is not equal to 0
cout<<white<<" "; } // displays W when above if condition is false
cout<<endl; } } //prints the new line
int main(){ //start of the main function
int num; //declares an integer num
cout << "Enter an integer representing the size of the chessboard: "; //prompts user to enter size of chess board
cin >> num; //reads value of num from user
chessboard(num); } //calls chessboard function to display N lines consist of N space-separated characters representing the chessboard pattern
Explanation:
The function works as follows:
Lets say that N = 2
two string variables black and white are declared. The value of black is set to "B" and value of white is set to "W" to return a chessboard pattern in B and W squares.
The outer loop for(i=1;i<=N;i++) iterates through each column of the chess board. The inner loop for(j=1;j<=N;j++) iterates through each row of chess board.
At first iteration of outer loop:
N = 2
outer loop:
i=1
i<=N is true because i=1 and 1<=2
So the program enters the body of the outer for loop. It has an inner for loop:
for(j=1;j<=N;j++)
At first iteration of inner loop:
j = 1
j<=N is true because j=1 and 1<=2
So the program enters the body of the inner for loop. It has an if statement:
if((i+j)%2==0) this statement works as:
if(1+1) % 2 == 0
(1+1 )% 2 takes the mod of 1+1 with 2 which gives the remainder of the division.
2%2 As 2 is completely divisible by 2 so 2%2 == 0
Hence the if condition evaluates to true. So the statement in if part executes:
cout<<black<<" ";
This prints B on the output screen with a space.
B
The value of j is incremented to 1.
j = 2
At second iteration of inner loop:
j = 2
j<=N is true because j=2 and 2=2
So the program enters the body of the inner for loop. It has an if statement:
if((i+j)%2==0) this statement works as:
if(1+2) % 2 == 0
(1+2 )% 2 takes the mod of 1+2 with 2 which gives the remainder of the division.
3%2 As 3 is not completely divisible by 2
Hence the if condition evaluates to false. So the statement in else part executes:
cout<<white<<" ";
This prints W on the output screen with a space.
B W
The value of j is incremented to 1.
j = 3
Now
j<=N is false because j=3 and 3>2
So the loop breaks and program moves to the outer loop to iterate through the next row.
At second iteration of outer loop:
N = 2
outer loop:
i=2
i<=N is true because i=2 and 2 = 2
So the program enters the body of the outer for loop. It has an inner for loop:
for(j=1;j<=N;j++)
At first iteration of inner loop:
j = 1
j<=N is true because j=1 and 1<=2
So the program enters the body of the inner for loop. It has an if statement:
if((i+j)%2==0) this statement works as:
if(2+1) % 2 == 0
(2+1 )% 2 takes the mod of 2+1 with 2 which gives the remainder of the division.
3%2 As 3 is not completely divisible by 2
Hence the if condition evaluates to false. So the statement in else part executes:
cout<<white<<" ";
This prints W on the output screen with a space.
B W
W
The value of j is incremented to 1.
j = 2
At second iteration of inner loop:
j = 2
j<=N is true because j=2 and 2=2
So the program enters the body of the inner for loop. It has an if statement:
if((i+j)%2==0) this statement works as:
if(2+2) % 2 == 0
(2+2 )% 2 takes the mod of 2+2 with 2 which gives the remainder of the division.
4%2 As 4 is completely divisible by 2 so 4%2 == 0
Hence the if condition evaluates to false. So the statement in if part executes:
cout<<black<<" ";
This prints B on the output screen with a space.
B W
W B
The value of j is incremented to 1.
j = 3
Now
j<=N is false because j=3 and 3>2
So the loop breaks and program moves to the outer loop. The value of outer loop variable i is incremented to 1 so i = 3
N = 2
outer loop:
i=3
i<=N is false because i=3 and 3>2
So this outer loop ends.
Now the output of this program is:
B W
W B
Screenshot of this program along with its output is attached.
I’m so confused on this but hey here’s this
