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2 years ago

What is the approximate total to the nearest whole number? 74.198 + 640.21

Mathematics

2 answers:

tatuchka [14]2 years ago

8 0

74.198+640.21=714.409
we round the 0.4
since 4<5 we round down
714 is answer

ioda2 years ago

5 0

74.198 + 640.21 = 714.408 ≈ 714
(it is nearer from 714 than from 715)

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The general solution is

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Step-by-step explanation:

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Given differential equation y(4) − 2y''' + y'' = e^x + 1

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The roots are m=0,0 and m =1,1

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<u>Step 2</u>:-

The particular equation is $\frac{1}{f(D)} Q$

P.I = $\frac{1}{D^2(D-1)^2} e^x+1$

P.I = $\frac{1}{D^2(D-1)^2} e^x+\frac{1}{D^2(D-1)^2}e^{0x}$

P.I = $I_{1} +I_{2}$

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$\frac{1}{D} means integration$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x = \frac{1}{2D} \int\limits {x^2e^x} \, dx$

applying in integration u v formula

$\int\limits {uv} \, dx = u\int\limits {v} \, dx - \int\limits ({u^{l}\int\limits{v} \, dx } )\, dx$

$I_{1}$ = $\frac{1}{D^2(D-1)^2} e^x$

$\frac{1}{2D} (e^x(x^2)-e^x(2x)+e^x(2))$

$\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

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Answer:

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Step-by-step explanation:

At first we should know the following about the rhombus

1) All sides are congruent

2) The diagonals are perpendicular and bisects each other.

Given UV = 8 and WX = 5

So, according to (1)

TU = UV = VW = WT = 8

And according to (2)

WX = UX = 5

And ΔWXV is a right triangle at ∠x

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So, XV = XT = √39

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