The probability of one arrives within the next 10 minutes
when he already been waiting for one jour for a taxi is,
P (X > 70 | X > 60) = P (X > 10) = 1 – P (X ≤ 10)
= 1 – {1 – e ^ -((1 / 10) 10)} = e ^ -1
= 0.3679
The probability of one arrives within the next 10 minutes
when he already been waiting for one hour for a taxi is 0.3679
The answer I'm pretty sure is B but I can't really explain it, sorry
<span><span><span>s+12</span>+<span>3s</span></span>−8</span><span>=
<span><span><span><span>s+12</span>+<span>3s</span></span>+</span>−8
</span></span>Combine Like Terms<span>
<span><span><span>s+12</span>+<span>3s</span></span>+<span>−8</span></span></span><span>=
<span><span>(<span>s+<span>3s</span></span>)</span>+<span>(<span>12+<span>−8</span></span>)</span></span></span><span>=
<span><span>4s</span>+<span>4</span></span></span>
The answer for this problem is 7
Answer:
i think its The sale price of the jeans is 50% of the original price.
Step-by-step explanation:
