Answer:
The equation which represents the question is 3 1/3
Answer:
D
Step-by-step explanation:
Plug in and see.
Check A: Lets plug in (0,3) into y<2/3 x+2.
3<2/3 (0)+2
3<2 is not true so not A
Check C: Lets plug in (3,5) into y<2/3 x+2.
5<2/3 (3)+2
5<2+2
5<4 is not true so not C
Check B: Lets plug in (-3,1) into y<2/3 x+2.
1<2/3 (-3)+2
1<0 is not true so not B
Check D: Lets plug in (1,2) into y<2/3 x+2.
2<2/3 (1)+2
2<2/3+2 is true so D
The least is 2/7 then 1/2 then 5/6 and the greatest is 4/2
You can make the mixed number 5 2/3 an improper fraction, which is the number in the numerator is larger than the number in the denominator.
Multiply, Add, and Keep the denominator are the steps you need to take.
Multiply the denominator by the whole number and then add the number in the numerator, while keeping the denominator. 5*3+2=17>>> 17/3 is the improper fraction.
17/3 ÷ 2 is the resulting equation.
When you divide fractions, you have to multiply by the reciprocal. 2/1 is the whole number 2, but in fraction form. The reciprocal is 1/2 because your just flipping the numerator and the denominator.
17/3 * 1/2 is the new equation.
When you multiply fractions, you multiply straight across.
17/3 * 1/2 = 17/6 or 2 5/6 is your answer.
Answer:
Step-by-step explanation:
sqrt(28): sqrt(4*7)
sqrt(4) = 2;
sqrt28)=2*sqrt(7)
sqrt(343): sqrt(7 * 7 * 7) = 7 * sqrt(7)
Note: the rule is if you have 3 equal primes under the root sign, you leave one, you throw one away, and you put one outside the root sign.
2 sqrt(63) = 2 sqrt(3*3*7) The above rule gets modified to throw 1 three away and take the other one outside the root sign.
2sqrt(63) = 2*3 sqrt(7)
Numerator: 2*sqrt(7) + 7sqrt(7) = 9sqrt(7)
9sqrt(7)
======
6 sqrt(7)
3/2
Note without brackets I cannot be certain that I have interpreted this correctly. The division only apply to sqrt(343) / 2 sqrt(63). If this is so please leave a note.
