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stira [4]
3 years ago
5

Find the dimensions of a rectangle with perimeter 76 m whose area is as large as possible. m (smaller value) m (larger value)

Mathematics
1 answer:
Sladkaya [172]3 years ago
5 0

Answer:

19 m

Step-by-step explanation:

Perimeter = 2(length + width) ; P = 2(l+w) - - (1)

Area = Length * width ; A = l*w - - - (2)

76 = 2(l+w)

76/2 = l+w

l+w = 38

l = 38 - w

Put l = 38 - w in (1)

A = (38-w)*w

A = 38w - w²

At maximum point:

dA/dw = 0

dA/dw = 38 - 2w

38 - 2w = 0

38 = 2w

w = 38/2

w = 19

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3 years ago
The quadratic equation is
NemiM [27]

Answer:

(2,-9)

Step-by-step explanation:

Set the quadratic equal to zero.

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Factor

(x - 5)(x + 1)

Set each of these factors to zero

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Plot the midpoint of the two values.

( \frac{5 + ( - 1)}{2} ) = 2

So the middle term is 2 and the other terms are 5 and -1.

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8 0
3 years ago
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Furkat [3]
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4 0
3 years ago
Determine the value of c in the diagram.
Neporo4naja [7]

Answer:

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3 0
3 years ago
12x – 10 = 134<br><br><br><br> 10<br><br><br> 9<br><br><br> 12<br><br><br> 16
Ymorist [56]

Answer:

shown below

explanation:

<em>first</em><em> </em><em>off</em><em>,</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>the</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em> </em><em>and</em><em> </em><em>1</em><em>3</em><em>4</em>

12x=134+10

12x=144

<em>then</em><em> </em><em>you</em><em> </em><em>simplify</em><em> </em><em>which</em><em> </em><em>will</em><em> </em><em>look</em><em> </em><em>like</em><em> </em><em>this</em><em>:</em>

12x. 144

___ = ___

12. 12

144÷12=12

so the answer is option c.12

<h2>hope it helps!!</h2>
7 0
3 years ago
Read 2 more answers
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