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stira [4]
3 years ago
5

Find the dimensions of a rectangle with perimeter 76 m whose area is as large as possible. m (smaller value) m (larger value)

Mathematics
1 answer:
Sladkaya [172]3 years ago
5 0

Answer:

19 m

Step-by-step explanation:

Perimeter = 2(length + width) ; P = 2(l+w) - - (1)

Area = Length * width ; A = l*w - - - (2)

76 = 2(l+w)

76/2 = l+w

l+w = 38

l = 38 - w

Put l = 38 - w in (1)

A = (38-w)*w

A = 38w - w²

At maximum point:

dA/dw = 0

dA/dw = 38 - 2w

38 - 2w = 0

38 = 2w

w = 38/2

w = 19

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11, 12, 30

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Step-by-step explanation:

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On a number​ line, suppose the coordinate of A is​ 0 and AR=21. What are the possible coordinates of the midpoint of AR?
Gnoma [55]

Answer:

The possible coordinates of the midpoint are -10.5 and 10.5

Step-by-step explanation:

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When R is on the left side of A, which is = 0 - 21 = -21, we have;

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4 0
4 years ago
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