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stepladder [879]
3 years ago
9

Jayden and Chandra are cleaning the house. It has 12 rooms, and each room is about the same size. When Jayden cleans by himself,

it takes him 6 hours. When Chandra cleans by herself, it takes her 12 hours. When they clean the house together, they finish in 4 hours. When they work together, how many rooms does Jayden clean and how many does Chandra clean? Show your work.
Please show work.


And label the answer like Jayden = blankrooms and Chandra = blankrooms. Thank you!
Mathematics
1 answer:
madam [21]3 years ago
6 0
We know that

Jayden cleans 12 rooms in---------------> <span>6 hours
 X rooms-------------------------------------> 4 hours
X=4*12/6--------> 48/6---------> 8 rooms
that means  </span>Jayden  cleans in 4 hours 8 rooms

Chandra cleans 12 rooms in---------------> 12 hours
 X rooms-------------------------------------> 4 hours
X=4*12/12--------> 48/12---------> 4 rooms
that means Chandra  cleans in 4 hours 4 rooms

the answer is
<span>Jayden = 8 blankrooms
</span><span>Chandra = 4 blankrooms</span>
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X^2 - 10x + 36 = 0;
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Which function represents g(x), a reflection of f(x) = 6(one-third) Superscript x across the y-axis?
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The function g(x)=6(3)^{x} represents a reflection of f(x)=6(\frac{1}{3})^{x} across the y-axis ⇒ 3rd answer

Step-by-step explanation:

Let us revise the reflection across the axes

  • If the function f(x) reflected across the x-axis, then its image is g(x) = - f(x)
  • If the function f(x) reflected across the y-axis, then its image is g(x) = f(-x)

∵ f(x)=6(\frac{1}{3})^{x}

∵ g(x) is the image of f(x) after reflection across the y-axis

- From the rule above reflection across the y-axis changes the sign of x

∴ g(x)=6(\frac{1}{3})^{-x}

∵ (a)^{-n}=(\frac{1}{a})^{n}

∵ (\frac{1}{a})^{-n}=(a)^{n}

∴ (\frac{1}{3})^{-x}=(3)^{x}

∴ g(x)=6(3)^{x}

The function g(x)=6(3)^{x} represents a reflection of f(x)=6(\frac{1}{3})^{x} across the y-axis

Learn more:

You can learn more about reflection in brainly.com/question/5017530

#LearnwithBrainly

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Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute
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Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

       = 3 - 1 = 2

d.f.D = N - k

        = 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust                      Jet red                 Cloudtran

$\overline X_1 =50.5$           $\overline X_2 =50.07143$        $\overline X_3 =55.71429$

$s_1^2=19.96154$      $s_2^2=14.68681$         $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

         $=\frac{51+51+...+49+49}{35}$

        = 52.1714

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$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

     $=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

   $=\frac{127.1143}{2}$

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    $=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

   $=\frac{669.8571}{32}$

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The F-test  statistics value is :

$F=\frac{s_B^2}{s_W^2}$

  $=\frac{63.55714}{20.93304}$

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So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source       Sum of squares    d.f    Mean square    F

Between    127.1143                 2      63.55714          3.036212

Within        669.8571             32      20.93304

Total           796.9714            34

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Step-by-step explanation:

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In most cases, there are two types of functions that have horizontal asymptotes. Functions in quotient form whose denominators are bigger than numerators when x is large positive or large negative.

Step-by-step explanation:

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