The answers are B and D hope this helps.
6 goodie bags. 6 is the greatest common factor of 54 and 36.
<span>9 tickets and 6 posters in each bag.</span>
Cos is the adjacent (side next to the angle in question) divided by the hypotenuse (sloped side)
for angle K, this is therefore 7/25
Answer:
Therefore we can say that 98 boxes will be needed to hold all the paperweights.
Step-by-step explanation:
i) there are 1657 souvenir paperweights that need to be packed in boxes.
ii) each box will hold 17 paperweights
iii) therefore the number of boxes that will be needed are
=
=
= 97.471
iv) Therefore we can say that 98 boxes will be needed to hold all the paperweights.