Yes it is possible,t<span>hey never intersect, so there is </span>no<span> point that lies on both lines, and </span>no solution<span> to the </span><span>system</span>
Answer:
48.2
Step-by-step explanation:
√(x2-x1)²+(y2-y1)²
√(15.3-59.5)² +(14.9-34.2)²
√(-44.2)² + (-19.3)²
√1953.64+372.49
√2326.13
48.2
Answer: Option D
Step-by-step explanation:
Soup : 15/5 is 3 x 7 is 21
Peanut: 35/7 is 5 x 5 is 25
First you plot in the y-intercept of the equation. To find the y-intercept, substitute 0 into x. -3m will cancel our giving you y=5. x=0, y=5, the first ordered pair is (0,5). Now after you plot in the y-intercept, use your slope, which is -3, to graph the points of the equation. Starting from (0,5), move down 3 spaces on the y-axis (because it’s -3) and you’ll end up at (0,2). Next move over 1 ( all slopes with just a whole number moves on the x-axis 1 since the whole number divided by 1 doesn’t change the slope number) to the right because it’s a negative linear equation so it’ll go downward. After moving right, you’ll get (1,2). Do a couple more points starting from (1,2) then the 3rd point ABD and so on to get 3 or more points to be able to draw a linear line.
