What is the solution to log Subscript 5 Baseline (x + 30) = 3
1 answer:
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Answer:
Option C is correct.
Step-by-step explanation:
Distance already traveled by Ed miles
Also, Ed is driving at a rate of 63 miles per hour.
Distance Speed × Time
Distance traveled by Ed in hours
Total distance traveled by Ed
Also, total distance traveled by Ed is miles.
Therefore,
Option C is correct.
Answer: He bought 2.89 pounds of cameo apples.
Step-by-step explanation:
Since we have given that
Total number of pounds of apples he bought = 4.08
Number of gala apples = 1.19 pounds
So, the rest are cameo apples.
As we know to get the remaining value we always use the subtraction operation,
Now,
So, 2089 pounds of apple are cameo apples.
Answer:
C: I and III only.
Step-by-step explanation:
We have two numbers x and y such that:
And we want to determine which of the following conditions must be true.
First, let's examine the third condition. We have:
To see if this is true, let's try a negative value for y. So, let's use -7. This will give:
Simplify:
This is saying we need a number less than -7 and greater than 7.
This is impossible. So, y <em>must be</em> greater than 0.
Therefore, Condition III must be true.
Next, let's see this compound inequality visually.
Picture the following number-line:
<----------(-y)----------0----------y---------->
Whatever y is, -y is just y on the negative side.
Now, since our condition is that -y<x<y, this means that our x can be anywhere between -y and y. Namely:
<----------(-y)----------0----------y---------->
To determine our correct condition, let's picture x anywhere on the bolded lines. I'm just going to put x here...
<----------(-y)-------(x)--0----------y---------->
Now, remember the alternative definition for absolute value. Namely, the absolute value of x is also the <em>distance</em> from 0 to x. And this distance is always positive.
Since our x is between -y and y, our distance from 0 to x will always be less than the distance from 0 to either y.
Therefore, Condition I is also true.
Let's try an example. Let's let y = 9. So, -y=-9. And let's let x be between 9 and -9, say, -2. So:
<---(-9)-----(-2)--0--------(9)------>
We can see that:
Also, this example counters Condition II, as our x can indeed be negative if we desire it.
Algebraically, if we have a negative x such that:
We can divide everything by -1 to obtain:
We can flip this to get:
Which is our original inequality. So, Condition II does not need to be true.
So, the two conditions that <em>must</em> be true is I and III.
So, our answer is C.