Answer:
3x4=12, plus 2 = 14, so it has to be 4, so 3(4) + 2 = 14 (answer is 4 if my explanation confused you)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given dimensions of a pyramid:
Length = l = 4 feet
Width = w = 4 feet for square base (w=l)
Height = h = 6 feet
The formula to find the area of square pyramid is =
=>
=>
=>
=>
=>
The monthly payment for this purchase with a price of $450, a finance charge of $82.50, a down payment of $150, and 18 monthly payments is <u>c.) $21.25</u>.
<h3>What is the monthly payment?</h3>
The monthly payment is the periodic payment made to settle a mortgage loan.
When the total mortgage payment is determined, the monthly payment can be calculated as the dividend of the total mortgage payment and the number of monthly payments.
<h3>Data and Calculaitons:</h3>
Purchase Price: $450
Finance Charge: $82,50
Down Payment: $150
Number of Payments: 18
Total mortgage payment = $382.50 ($450 + 82.50 - 150)
Monthly payment = $21.25 ($382.50/18)
Thus, the monthly payment for this purchase with a price of $450, a finance charge of $82.50, a down payment of $150, and 18 monthly payments is <u>c.) $21.25</u>.
Learn more about monthly payments at brainly.com/question/25658911
#SPJ1
Half the perimeter is the length + the width.
Let the width = x
The length is x + 4. ( 4 feet more than the width)
Now you have x + x + 4 = 20
Combine like terms:
2x + 4 = 20
Subtract 4 from both sides:
2x = 16
Divide both sides by 2:
X = 8
The width is 8 feet
The length is 8 + 4 = 12 feet
Answer:
m∠FEH = 44°
m∠EHG = 64°
Step-by-step explanation:
1) The given information are;
The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°
Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°
Therefore, angle subtended by arc ∠HGF at the center = 88°
The angle subtended by arc ∠HGF at the circumference = m∠FEH
∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)
m∠FEH = 44°
2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°
The sum of angles in a quadrilateral = 360°
Therefore;
m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)
m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°
m∠EHG = 64°.