The website of an international human rights organization stores a large database of information and provides search functionali
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PSEUDOCODE:
1. DECLARE number: INTEGER
2. DECLARE multiple: INTEGER
3. INPUT number
4. FOR counter FROM 1 TO 10 DO
5. multiple <-- number * counter
6. PRINT number, " * ", counter, " = ", multiple
7. ENDFOR
<em>1. declaring a variable "number" as an Integer</em>
<em>2. declaring a variable "multiple" as an Integer</em>
<em>3. The user inputs the value of number</em>
<em>4. FOR loop where variable "counter" increments by 1 after every iteration</em>
<em>5. sets the value for variable "multiple" as the value of number * counter</em>
<em>6. prints out for example "3 * 1 = 3" and will continue till counter reaches 10</em>
<em>7. Ends the for loop</em>
FLOWCHART below
hope it helped
Answer:
Explanation:
The following code is written in Python. It asks the user for an input. Then cleans the input using regex to remove all commas, whitespace, and apostrophes as well as making it all lowercase. Then it reverses the phrase and saves it to a variable called reverse. Finally, it compares the two versions of the phrase, if they are equal it prints out that it is a palindrome, otherwise it prints that it is not a palindrome. The test case output can be seen in the attached picture below.
import re
phrase = input("Enter word or phrase: ")
phrase = re.sub("[,'\s]", '', phrase).lower()
reverse = phrase[::-1]
if phrase == reverse:
print("This word/phrase is a palindrome")
else:
print("This word/phrase is NOT a palindrome")
