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SVEN [57.7K]
3 years ago
7

Covert the fraction to a decimal. 1 1/3

Mathematics
2 answers:
cupoosta [38]3 years ago
6 0

Step-by-step explanation:

Answer

311=0.272727...............

311

= 3011×(110)

= 22+811×110

= 2211×110+811×110

= 2×110+8011×1100

= 210+77+311×1100

= 210+7711×1100+311×1100 or

311=210+7100+1100×(311) ........(A)

Now using value of 311 from (A) within (A)

311=210+7100+1100×(210+7100+1100×(311))

= 210+7100+21000+710000+110000×(311))

Now, if we keep on repeating this endlessly

311=210+7100+21000+710000

Tpy6a [65]3 years ago
6 0

Answer:

1.33

Step-by-step explanation:

1 is just 1. 1/3 is .33. Add them together and you get 1.33

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71

Step-by-step explanation:

<u>refer</u><u> </u><u>the</u><u> attachment</u>

to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that <u>tangents </u><u>which</u><u> </u><u>meet </u><u>at</u><u> the</u><u> </u><u>same</u><u> </u><u>point</u><u> </u><u>are </u><u>equal</u><u> </u><u> </u>that is being said

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since \rm BA=FA+FB and it's given that FA and BA are 17 and 29 FB should be

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thus,

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By the theorem we obtain:

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Similarly,DC=DG+CH therefore,

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Now <u>finding</u><u> </u><u>the</u><u> </u><u>Perimeter</u><u> </u><u>of </u><u>ABCD</u>

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substitute what we have and got

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simplify addition:

  • P_{\text{ABCD}}=\boxed{71}

hence,

the Perimeter of ABCD is <u>7</u><u>1</u>

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