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yawa3891 [41]
3 years ago
13

The graph below shows the prices of different numbers of boots at a store: A graph is shown. The values on the x axis are 0, 2,

4, 6, 8, and 10. The values on the y axis are 0, 25, 50, 75, 100, and 125. Points are shown on ordered pairs 0, 0 and 2, 25 and 4, 50 and 6, 75 and 8, 100. These points are connected by a line. The label on the x axis is Number of Boots. The title on the y axis is Price in dollars. Which equation can be used to determine p, the cost of b boots? p = 12.50b p = 25b b = 25p b = 12.50p
Mathematics
2 answers:
kobusy [5.1K]3 years ago
5 0

Answer:

b=12.50p

Step-by-step explanation:

Given :

x                 y

0                 0

2                 25

4                 50

6                 75

8                 100

10                125

To Find: Which equation can be used to determine p, the cost of b boots?

Solution :

Using point slope form Find the equation of line of the given coordinates

Let (x_{1} , y_{1})=(0,0)

Let (x_{2} , y_{2})=(2,25)

So, formula : y-y_{1} =\frac{y_{2}- y_{1}}{x_{2}- x_{1}} *(x-x_{1})

y-0 =\frac{25-0}{2-0} *(x-0)

y= 12.50x

Now we are given that cost of b boots is p

Since we are given that x axis is Number of Boots and y in price

So in the equation put x = b and y = p

So, equation : b=12.50p

Hence Option 4 is correct

irinina [24]3 years ago
4 0

Answer:

The answer is p=12.50b

Step-by-step explanation:

The reason for this is because the price is equal to how many boots, b, times 12.50, so you would right this as p=12.50b

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3 years ago
Anne deposited $500 in an account that earns 6% simple annual interest. Shelly deposited $500 in an account that earns 6% annual
Inga [223]

Answer:

It is clear that, The Shelly account is $11.23 more than that in Anne account .

Step-by-step explanation:

Given as :

For Anne

The amount deposited in account = p = $500

The rate of interest = r = 6%  at simple interest

The time period of deposit = t = 4 years

Let The amount received in account after 4 years = $A_1

<u>From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or, s.i = \dfrac{\textrm p\times \textrm r\times \textrm t}{100}

Or, s.i = \dfrac{\textrm 500\times \textrm 6\times \textrm 4}{100}

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i.e s.i = $120

∵ Amount = Principal + Interest

Or, A_1 = p + s.i

Or A_1 = $500 + $120

Or, Amount = $620

So, The Amount in Anne account after 4 years is $620

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For, Shelly

The amount deposited in account = P = $500

The rate of interest = R = 6% compounded annually

The time period of deposit = T = 4 years

Let The amount received in account after 4 years = $A_2

<u>From Compound Interest method</u>

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, A_2 = P × (1+\dfrac{\textrm R}{100})^{\textrm T}

Or, A_2 = $500 × (1+\dfrac{\textrm 6}{100})^{\textrm 4}

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So, The amount received by Shelly in her account after 4 years = $631.23

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i.e  A_2 -  A_1 = $631.23 - $620

Or, A_2 -  A_1 = $11.23

Hence, It is clear that, The Shelly account is $11.23 more than that in Anne account . Answer

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