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3 years ago

What is going onI am confused

Mathematics

2 answers:

nikdorinn [45]3 years ago

6 0

?????? what do you mean

Verizon [17]3 years ago

3 0

Answer:

What do you mean?

Step-by-step explanation:

I would suggest adding more info

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A building makes a 90° angle with the ground. A ladder leans against the building, making a 110° exterior angle with the ground.

liberstina [14]

<u>Answer:</u>

A building makes a $90^{\circ}$ angle with the ground .The two interior angles are $70^{\circ}$ and $20^{\circ}$

<u>Solution: </u>

Given, a ladder which is against the building wall makes an exterior angle of $110^{\circ}$

And building makes a $90^{\circ}$ angle with the ground.

So, altogether it makes a right angle triangle with ladder as hypotenuse and ground as base leg and building as another leg.

Now, we know that, sum of exterior angles and interior angles equals to $180^{\circ}$

Here, in the case of ground and ladder, exterior angle is $110^{\circ}$ and interior angle is unknown.

Exterior angle + interior angle = 180

110 + interior angle = 180

Interior angle = 180 – 110

Interior angle = $70^{\circ}$

We have found one of the two interior angles of right angle triangle.

We know that, sum of angles in a triangle is 180 degree

Known Interior angle + unknown interior angle + right angle = 180

70 + unknown interior angle + 90 = 180

Unknown interior angle + 160 = 180

Unknown interior angle = 180 - 160

Unknown interior angle = $20^{\circ}$

Hence the two interior angles are $70^{\circ}$ and $20^{\circ}$

7 0

3 years ago

Obtain the total salary?)

Nonamiya [84]

Answer:

F(d) = 30 + 0.50d

Step-by-step explanation:

Given

Charges = P8.00 ---- first 4 km

Additional = P0.50

Required

Write a function to address the scenario.

Represent the whole distance covered with d.

First,we need to determine the total charges for the first four hours.

Charges = 8.00 * 4

Charges = 32.00

Next, we determine the charges for additional distance.

Charges = 0.50 * (d - 4)

d - 4 is the remaining distance after the first 4.

Charges = 0.50d - 2

The function is then written as;

F(d) = 32 + 0.50d - 2

F(d) = 32 - 2 + 0.50d

F(d) = 30 + 0.50d

8 0

3 years ago

Mr. Brown's class is collecting books for a book drive. They started with 2 books. On the first day, they had 6 books. On the se

elena-s [515]

Answer:

the answer is b i click it and it was right

y=2(3)^x

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If you run for 0.4 hours at 7 mph, how fast should you walk during the next 0.8 hours to have the average speed of 5 mph?

Fantom [35]

Answer:

4 mph

Step-by-step explanation:

The average speed of an object is given by the total distance covered by the time taken:

$v=\frac{d}{t}$

where

d is the total distance covered

t is the time taken

in the first part, the person runs for 0.4 hours at a speed of 7 mph, so the distance covered in the 1st part is

$d_1 = v_1 t_1 = (7)(0.4)=2.8 mi$

Then the distance covered in the second part is $d_2$ , so the total distance is

$d=2.8+d_2$ (1)

The total time elapsed is 0.4 hours (first part) + 0.8 hours (second part), so

$t=0.4+0.8=1.2 h$

So we can write the average speed as

$v=\frac{2.8+d_2}{1.2}$ (1)

We want the average speed to be 5 mph,

v = 5 mph

Therefore we can rearrange eq.(1) to find d2:

$d_2 = 1.2v-2.8 = (1.2)(5)-2.8=3.2 mi$

And therefore, the speed in the second part must be

$v_2=\frac{d_2}{t_2}=\frac{3.2}{0.8}=4 mph$

4 0

3 years ago

At noon, ship A is 170 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 20 km/h. How fast is

garik1379 [7]

Check the picture below.

now, keep in mind that ship B is going at 20kph, thus from noon to 4pm, is 4 hours, so it has travelled by then 20 * 4 or 80 kilometers, thus b = 80.

whilst the ship B is moving north, the distance "a" is not really changing, and thus is a constant, that matters because the derivative of a constant is 0.

$\bf c^2=a^2+b^2\implies \stackrel{chain~rule}{2c\cfrac{dc}{dt}}=0+2b\cfrac{db}{dt}\implies \cfrac{dc}{dt}=\cfrac{b\frac{db}{dt}}{c}
\\\\\\
\begin{cases}
\frac{db}{dt}=20\\
c=10\sqrt{353}\\
b=80
\end{cases}\implies \cfrac{dc}{dt}=\cfrac{80\cdot 20}{10\sqrt{353}}\implies \cfrac{dc}{dt}=\cfrac{160}{\sqrt{353}}
\\\\\\
\textit{and rationalizing the denominator}\implies \cfrac{160\sqrt{353}}{353}$

8 0

3 years ago

What is going onI am confused ​

What is going onI am confused