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Lady bird [3.3K]
2 years ago
11

Solve the equation using the zero product property 0=x^2+3x-10

Mathematics
1 answer:
PolarNik [594]2 years ago
6 0
(X - 2)×(X + 5) = 0
X= 2 or -5
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anthonyś yearly budget for the furniture in his house is $18,000 he spent 9% of the budget on the family room how much did he sp
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Answer:

  $1620

Step-by-step explanation:

  9% of budget = 0.09 × $18000 = $1620

Anthony spent $1620 on the family room.

3 0
3 years ago
How do you find both lengths of the diagonals of a rhombus?
attashe74 [19]
To find the area of a rhombus, multiply the lengths of the two diagonals and divide by 2 The sides and angles of a rhombus The sides of a rhombus are all congruent Opposite angles of a rhombus are congruent
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2 years ago
What is the MAXIMUM amount you should be spending on housing in a situation where your GROSS INCOME is $2000 per month? 1. For r
almond37 [142]

Answer:

the answer is a

Step-by-step explanation:

i took the test on gogo.net

5 0
3 years ago
Tom read 20 books, 12 magazines, and 18 newspaper articles last year.
neonofarm [45]

Answer: 24% of the books read are magazine

Step-by-step explanation:sum of the books read is 20+12+18=50 books.

Therefore 12 of the books are magazine.

Then, 12 of 50 =24%( 12÷50)× 100/1 = 24%

8 0
3 years ago
Read 2 more answers
If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x
Andrei [34K]

Answer:

\large\boxed{A.\ (x+6)^2+(y+10)^2=20}

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-6, -10) and (-8, -6):

r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}

Finally we have

(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20

5 0
3 years ago
Read 2 more answers
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