Question

A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. Find the total area of the pyramid.

Answer 1

Area of the Base = 6 * side^2 / 4 * tan (180/6)
Area of the Base = 6 * 16 / 4 * 0.57735
Area of the Base = 96 / 2.3094
Area of the Base = 41.5692387633

Area of 1 Face = 2 * 6 = 12
Area of 6 Faces = 72

Total Area = 41.5692387633 + 72
Total Area = 113.5692387633

Answer 2

Answer:

Step-by-step explanation:

alright lets get started.

Total area of pyramid will be equals to the sum of area of base and the area of all six faces.

area of hexagonal will be = $\frac{3\sqrt{3} }{2} *a^2$

Plugging the value of a as 4, the area of base will be :

$\frac{3\sqrt{3} }{2}*4^2= 41.57$

Now the area of one face will be= $\frac{1}{2} *base*height$

so, the area of one face will be = $\frac{1}{2} * 4*6=12$

So, the area of six faces will be = $6*12=72$

So, the total area of pyramid will be = $41.57+72$

So, the total area of pyramid will be 113.57

Hence the answer is 113.57.      :   answer

Hope it will help :)