Answer:
Step-by-step explanation:
Perimeter of a rectangle = 2(L +W)
Given L = W + 2 and the perimeter is greater than 112 meters?
P rect < 2(L +W) L = W + 2
P rect < 2(W + 2 +W)
< 2(2W+2)
112 < 4W + 4 solve for W
(112 - 4)/4 < (4W +4 - 4)/4
108/4 < (4W + 0)/4
27 < W
the width has to be greater than 27 meters
Answer: it is 100% A
Step-by-step explanation:
Answer:
11 because 165÷25=11 so yeah
Answer:
33/4
Step-by-step explanation:
8x4 +1 = 33
In an isosceles triangle, there are two sides that are congruent.
In this case, AB and BC are congruent.
Knowing this, we know that AB = BC
Since we know the values of AB and BC, we can put them into the equation:
3x - 4 = 5x - 10
Subtract 3x from both sides:
-4 = 2x - 10
Add 10 to both sides to isolate 'x':
6 = 2x
Divide both sides by 2:
x = 3
Now that we know the value of the variable, we just have to input it into AB's equation:
3x - 4 = 3(3) - 4
3(3) - 4 = 9 - 4
9 - 4 = 5
<u>AB = 5</u>
Good luck!
