As follows
r-6=7
+6 +6
r= 13
Answer:
- -6x² - 6 = -7x - 9
- -6x² + 7x - 6 + 9 = 0
- -6x² + 7x + 3 = 0
- 6x² - 7x - 3 = 0
<u>Discriminant:</u>
- D = (-7)² - 4*6*(-3) = 49 + 72 = 121
<u>Since D > 0, there are 2 real solutions:</u>
- x = (- (-7) ±√121 )/12
- x = (7 ± 11)/12
- x = 1.5, x = -1/3
Ok, so we see in
y=a(x-h)^2+k
vertex is (h,k)
vertex is highest or lowest point
on one side, it goes up and other side it goes down
if a is positive, then it goes down then up
if a is negative, it goes up then down
we see
f(x)=2(x+3)^2+2
2 is positive
goes down then up
vertex is (-3,2)
so decreases from -infinity to -3 or ininterval
(-infinity,-3)
answer is first option
Answer:
f(8) = -9
Step-by-step explanation:
Substitute 8 in for x.
f(8) = -2(8) + 7
f(8) = -16 + 7
f(8) = -9
