Magnitude of force= |F|= 5 lb
In the direction of vector,let say M=5i-3j
As, we know that vector consists of magnitude and direction( unit vector)
F=|F| M(unit vector).........1
In order to find the unit vector, divide the vector M by its magnitude.
M(unit vector)=(5i-3j)/√34
Now, the eq. 1 becomes
F=5(5i-3j)/√34
F=(25i-15j)/√34
As, the object moves from point let say P=0i+6j to Q=7i-4j
so,
PQ=Q-P
=(7-0)i+(-4-6)j
=7i - 10j
So,
W= F.PQ
=((25i-15j)/√34).(7i-10j)
=(7*25/√34)+(-10*-15/√34)
=55.7 lb*ft
=56 lb*ft
Option C is correct
Answer:
(i) the other two sides are 6 and 6
(ii) the other two sides are 
Step-by-step explanation:
(i) Sine: sin(θ) = Opposite ÷ Hypotenuse
Cosine: cos(θ) = Adjacent ÷ Hypotenuse
Tangent: tan(θ) = Opposite ÷ Adjacent
Here adjacent side = 6
opposite side = d
angle = 45°
other angles are 90° and 45°
tan (45) = Opposite ÷ Adjacent
1 = d ÷ 6
∴ d = 6 × 1 = 6
so opposite side = 6
Hypotenuse ² = opposite side ² + adjacent side²
= 6² + 6²
= 36 + 36
= 72
hypotenuse = 
= 6
the other two sides are 6 and 6
(ii) here adjacent side = 4√3
angle = 30°
other angles are 90° and 60°
opposite side = d
tan ( 30) = opposite ÷ adjacent
= d ÷ 4√3
= d × (
)
3 d = 4
therefore d = 
therefore opposite side = 
Hypotenuse ² = opposite side ² + adjacent side²
=(
)² +(
)²
= 
therefore hypotenuse = 
=
the other two sides are 
The answer is A) 59
9/5(15)+32 =59
Answer:
c = 6.1
Step-by-step explanation:
Given that: B = 18°
, C = 152°, and b = 4.
The missing side, c, can be determined by applying the sine rule which states that:
= 
= 
c = 
= 
= 6.0773
c = 6.1
Therefore, the value of the missing side, c, is 6.1
Answer:
5 and 1/2
Step-by-step explanation: 2 goes into 11 5 times without passing it. That one that is left over would be the numerator and 2 as the demonator.