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3 years ago

11

Please provide the working outs as well as the answer. Many thanks

1 answer:

lana [24]3 years ago

4 0

$\dfrac{3w-5}{2}=w-3\ \ \ |multiply\ both\ sides\ by\ 2\\\\\not2^1\cdot\dfrac{3w-5}{\not2_1}=2\cdot w-2\cdot3\\\\3w-5=2w-6\ \ \ |add\ 5\ to\ both\ sides\\\\3w-5+5=2w-6+5\\\\3w=2w-1\ \ \ \ |subtract\ 2w\ from\ both\ sides\\\\3w-2w=2w-2w-1\\\\\boxed{w=-1}$

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erik [133]

We have to find the mass of the gold bar.

We have gold bar in the shape of a rectangular prism.

The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.

First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:

Volume of the gold bar $= length \times width\times height$

Plugging the values in the equation we get,

Volume of the gold bar $=18.00 \times 9.21 \times 4.45= 737.721cm^3$

Now that we have the volume we can find the mass by using the formula,

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The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:

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3 years ago