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DiKsa [7]
3 years ago
7

The attic floor, ABCD in the model, is a square. The beams that support the roof are the edges of a block (rectangular prism) EF

GHKLMN. E is the middle of AT, F is the middle of BT, G is the middle of CT and H is the middle of DT. All the edges of the pyramid in the model have length 12m.
Calculate the area of the attic floor ABCD.
Mathematics
1 answer:
erastova [34]3 years ago
8 0

Answer:

<u>The area of ABCD = 12² = 12 * 12 = 144 m²</u>

Step-by-step explanation:

Given that ABCD in the model, is a square.

All the edges of the pyramid in the model have length 12m.

So, the length of one side of the square = 12 m

The area of the square = (side length)²

∴ the area of ABCD = 12² = 12 * 12 = 144 m²

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4 0
2 years ago
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Which of the following graphs best represents the solution to the pair of equations below? y = −x + 6 y = 2x − 3 A coordinate pl
Lera25 [3.4K]
The lines are 

i)  y=-x+6
ii) y=2x-3

The solution of the system of equations is found by equalizing the 2 equations:

-x+6=2x-3

-2x-x=-6-3

-3x=-9

x=-9/(-3)=3

substitute x=3 in either i) or ii):

i)  y=-3+6=3
ii) y=2(3)-3=6-3=3

(the result is the same, so checking one is enough)

This means that the point (3, 3) is a point which is in both lines, so a solution to the system.

In graphs, this means that the lines intersect at (3, 3) ONLY


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3 years ago
Write the absolute value equation given the transformations
Evgesh-ka [11]

Answer:

<em>y = - 0.5 | x - 5 | + 2</em><em> </em>

Step-by-step explanation:

g(x) = |x|

1^{st} step - shifts right 5 units: g(x + 5) = | x <u><em>- 5</em></u> |

2^{nd} step - shifts up 2 units: g(x + 5) + 2 = | x - 5 | <u><em>+ 2</em></u>

3^{rd} step - reflected: - g(x + 5) + 2 =<em> - </em>| x - 5 | + 2

4^{th} step - stretched by 0.5: <em>y = - </em><u><em>0.5</em></u><em> | x - 5 | + 2</em>

<em>y = - 0.5 | x - 5 | + 2</em>

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3 years ago
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Harlamova29_29 [7]

Answer:

The 6th term of the sequence is 25

Step-by-step explanation:

first term = a = 5

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The nth term of a sequence is

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Therefore, the 6th term of the sequence is

T_6 = a + (6 - 1)d

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T_6 = 5 + 20

T_6 = 25

3 0
3 years ago
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